Solve the IBVP below: PDE : Ux = (1/c²)uu for 0sxsL, t>0 ВС: и(0, () —0, и(L, t) %3 0 for t>0 2k х, L L 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the IBVP below:
PDE : Ux = (1/c²)uu
for 0sx<L, t>0
ВС:
u(0, () —0, и(L, t) %3 0
for t>0
2k
х,
L
for osx
L
0<x<-
IC:
u(x,0) = f(x) =:
2k
-(L-x),
L
L
for
2
u(x,0) = 0
for 0<x<L
Consider only the case when 1 = -p?
Transcribed Image Text:Solve the IBVP below: PDE : Ux = (1/c²)uu for 0sx<L, t>0 ВС: u(0, () —0, и(L, t) %3 0 for t>0 2k х, L for osx L 0<x<- IC: u(x,0) = f(x) =: 2k -(L-x), L L for 2 u(x,0) = 0 for 0<x<L Consider only the case when 1 = -p?
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