Solve the given IVP, or find the GS of the DE if no IC is given. 1 xy' = 3y - x, y(1) = 1. 2 2xy = x + y, y(1) = 3. 3 3xy' = x + 3y. 4 (x+y)y' = 2x - y, y(1) = -1-√√2. 6 x²y = xy + y². 5 (2x + y)y' = 3x - 2y, y(1) = -4. r²y' - 2xy - y² = 0, r²y' = 2x² - 2xy + y², y(1) = 3/2. (2x²2ry)y' = 4xy - 3y², y(3) = -3. y(1) = 0. 7 9 10 11 r²y = 4x² + xy + y², 13 r²y = r² - xy + y². y(1) = 1. 8 2x²y = 3x² - 2xy + y², y(1) = -1. 12 x²y = x² + xy + y², 14 (2xy - x²)y' = 3y²– 2xy - 2x², 15 (x² + 2xy)y' = 2xy - x² + 3y², y(2) = -4. 16 (2ry - 3x²)y' = 2x² - 6xy + 3y², y(3) = 3/2. 17 (2x² - xy)y' = xy - y². 19 3ry'y' = ³ + 3y³. y(1) = 0. y(1) = 3/2. 18 (2r²3ry)y' = x² + 2xy - 3y², y(1) = 0. 20 2xy²y' = r³+ y³, y(2) = 24/³¸
Solve the given IVP, or find the GS of the DE if no IC is given. 1 xy' = 3y - x, y(1) = 1. 2 2xy = x + y, y(1) = 3. 3 3xy' = x + 3y. 4 (x+y)y' = 2x - y, y(1) = -1-√√2. 6 x²y = xy + y². 5 (2x + y)y' = 3x - 2y, y(1) = -4. r²y' - 2xy - y² = 0, r²y' = 2x² - 2xy + y², y(1) = 3/2. (2x²2ry)y' = 4xy - 3y², y(3) = -3. y(1) = 0. 7 9 10 11 r²y = 4x² + xy + y², 13 r²y = r² - xy + y². y(1) = 1. 8 2x²y = 3x² - 2xy + y², y(1) = -1. 12 x²y = x² + xy + y², 14 (2xy - x²)y' = 3y²– 2xy - 2x², 15 (x² + 2xy)y' = 2xy - x² + 3y², y(2) = -4. 16 (2ry - 3x²)y' = 2x² - 6xy + 3y², y(3) = 3/2. 17 (2x² - xy)y' = xy - y². 19 3ry'y' = ³ + 3y³. y(1) = 0. y(1) = 3/2. 18 (2r²3ry)y' = x² + 2xy - 3y², y(1) = 0. 20 2xy²y' = r³+ y³, y(2) = 24/³¸
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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