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Solve the given differential equation. y" + 4y = 12y' The values c₁ and c₂ are arbitrary constants. Choose the correct answer below. A. y=c₁e (6+4√²) x + ₂x e (6-4√2) x C OB. e (6 + 4√² ) × + C₂ c (6 - 4√²) × y=C₁ e OC. y=c₁ cos (6+4√2)+c₂ sin (6-4√√2) D. y=C₁ e (−6+4√²) × + C₂ e (-6-4√2)x

Solve the given differential equation. y" + 4y = 12y' The values c₁ and c₂ are arbitrary constants. Choose the correct answer below. A. y=c₁e (6+4√²) x + ₂x e (6-4√2) x C OB. e (6 + 4√² ) × + C₂ c (6 - 4√²) × y=C₁ e OC. y=c₁ cos (6+4√2)+c₂ sin (6-4√√2) D. y=C₁ e (−6+4√²) × + C₂ e (-6-4√2)x

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve the given differential equation. y" + 4y = 12y' The values c₁ and c₂ are arbitrary constants. Choose the correct answer below. y=ce (6+442)x+oxe +4√2) OA. (6-4√2) x y=C₁ e e (6 + 4√² ) × + C₂ e (6 - 4√²) × OC. y=c₁ cos (6+4√2)+c₂ sin (6-4√2) OD. y=₁e (-6+4√2)x+C₂ e (-6-4√2)× О в.
Transcribed Image Text:Solve the given differential equation. y" + 4y = 12y' The values c₁ and c₂ are arbitrary constants. Choose the correct answer below. y=ce (6+442)x+oxe +4√2) OA. (6-4√2) x y=C₁ e e (6 + 4√² ) × + C₂ e (6 - 4√²) × OC. y=c₁ cos (6+4√2)+c₂ sin (6-4√2) OD. y=₁e (-6+4√2)x+C₂ e (-6-4√2)× О в.
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