Solve the frame USING: Portal Method Problem Solving: Round off your final answer to 2 decimal places.3m3m4 m*Members along Line 120 kN15 kN10 kN*Members along Line 312Di L4 HiCB100Regular Hexagon with side = 300 mmAlmmm3 m3 mFor the frame provided below, consider the following properties:*Members along Level 2L3 GSolve the following for ALL members:1. Axial Forces2. Shear Forces3. MomentsL2 FElmmEquilateral Triangle with side = 650 mm3نیاK!Jmm3 m*Members along Level 3Regular Trapezoid with longer side = 500 mm, shorter side = 400 mm, Height = 500 mm*Members along Level 4Regular Trapezoid with longer side = 300 mm, shorter side = 200 mm, Height = 400 mmM₁Hollow Circular Tube, Outer Diameter = 550 mm, Inner Diameter = 350 mm4mmmm*Members along Line 2Hollow Square Tube, Outer Breadth & Height = 500 mm, Inner Breadth & Height = 300 mm*Members along Line 4Hollow Circular Tube, Outer Diameter = 400 mm, Inner Diameter = 300 mm

Answered: Image /qna-images/answer/fe698a13-7c3e-4acc-8ede-cca206fafc9f.jpg

Answered: Solve the frame USING: Portal Method

Engineering

Civil Engineering

Solve the frame USING: Portal Method

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Frames

The trusses and frames are the two most important structural members of civil engineering. Trusses are the interconnection of links and other structural members. The interconnection with other members makes the system behave as a single member that supports and transfers loads. Trusses are generally two types, plane truss, and space truss. Frames on the other hand form the skeleton of any building construction. Frames are structures formed by the connection of beams, columns, slabs, and joists. These members provide the building with the required structural support.

Question

Solve the frame USING: Portal Method

Problem Solving: Round off your final answer to 2 decimal places.
3m
3m
4 m
*Members along Line 1
20 kN
15 kN
10 kN
*Members along Line 3
1
2
Di L4 Hi
C
B
100
Regular Hexagon with side = 300 mm
Al
mmm
3 m
3 m
For the frame provided below, consider the following properties:
*Members along Level 2
L3 G
Solve the following for ALL members:
1. Axial Forces
2. Shear Forces
3. Moments
L2 F
El
mm
Equilateral Triangle with side = 650 mm
3
نیا
K!
J
mm
3 m
*Members along Level 3
Regular Trapezoid with longer side = 500 mm, shorter side = 400 mm, Height = 500 mm
*Members along Level 4
Regular Trapezoid with longer side = 300 mm, shorter side = 200 mm, Height = 400 mm
M₁
Hollow Circular Tube, Outer Diameter = 550 mm, Inner Diameter = 350 mm
4
mmmm
*Members along Line 2
Hollow Square Tube, Outer Breadth & Height = 500 mm, Inner Breadth & Height = 300 mm
*Members along Line 4
Hollow Circular Tube, Outer Diameter = 400 mm, Inner Diameter = 300 mm

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Step 1: Given data

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Step 2: By using portal method to Finding the horizontal shears developed in each column of the frame:-

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Step 3: Finding the axial and shear forces of all members of the given frame:-

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Step 4: Finding axial forces shear forces of all members of the given frame:-

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