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Solve the following system by the method of reduction. - 4z= 16 2x-2y-2z= 24 2x+2y-2z= -4 4x+2y + 2z= -12 2x Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. x=y=_, 2= | (Type integers or fractions.) OB. x=r, y=z= (Type integers or fractions.) O C. There is no solution.

Solve the following system by the method of reduction. - 4z= 16 2x-2y-2z= 24 2x+2y-2z= -4 4x+2y + 2z= -12 2x Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. x=y=_, 2= | (Type integers or fractions.) OB. x=r, y=z= (Type integers or fractions.) O C. There is no solution.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the following system by the method of reduction. - 4z = 16 2x-2y-2z= 24 2x+2y-2z= -4 4x + 2y + 2z= -12 2x Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. x=y: ,z= (Type integers or fractions.) OB. x=r, y= ,Z = (Type integers or fractions.) OC. There is no solution.
Transcribed Image Text:Solve the following system by the method of reduction. - 4z = 16 2x-2y-2z= 24 2x+2y-2z= -4 4x + 2y + 2z= -12 2x Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. x=y: ,z= (Type integers or fractions.) OB. x=r, y= ,Z = (Type integers or fractions.) OC. There is no solution.
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