Solve the following system by Cramer's rule, where it applies = 2 + 22 = 3 + 2z 4x + 5y (a) 11x + 1 + 5y 3y + %3D %3D - (b) 2.x -2 4x 3z = 0 3x y + 4 -- (c) -x +7y 2z 1 - 2.x + 6y I||| II

Q: 3y3 (2y+3) (y-5)

A: The given expression is

Q: 3(y-2) 1- 3y

A:

Q: 8) Multiply: (2a-3)(5a + 1) a. 10a²-3 d. 10a²13a-3 b. 7a²-2 e. 10a²-6a-3 c. 7a²-5a-2

A:

Q: (2x)(x-y+5)(5y)

A: Firstly, we multiply 2x by each term of x-y+5

Q: (7a - 5b + 2c)- (-6a+8b - 4c) (7a - 5b + 2c) - (-6a+ 8b – 4c) =

A:

Q: 3. y = x2 - 2 -3 -2 -10 3D 2 3 X

A:

Q: 2y3(5y3-3y2+6y)

A: It the given that, the multiplication expression,

Q: 3(z+5)=12

A:

Q: If Ax) = Vx -1 and g(x) = x+ 1, which expression is equal to fAg(x))? 1+ー1 Wx²+2x (x + 1) - 1 ベズ+x-1

A: Solution:

Q: #6

A:

Q: (9) [xV1-2х dx

A:

Q: 2x+3x₂-x₂ = 7 3. Use Cramer's rule to solve 3x, -5x₂ =4 x₁ + x₂ = 5

A: