Solve the following system 3 Y1 = -y1 1 3/2 2 = Y2 + 5Y3 Y = 2y3 2уз (a) y1 = cie¯ + 2c3e2* C2e“ + C3e2 2cze2 (d) y1 = Cie' (c) Y1 = c1e¬² – c3e2a Y2 = C2eª (b) ул Ce- C3e2* 2x Y2 = c2e" + c3e2* Cze2r 92 = Y3 = 2cze2" -2x = cje 2x Y3 Y3 -2x Cze (е) Ул + 2c3e" -2x C2e 2x Y2 + cze" Y2 = C2e + Cze* -2x -2x Y3 2c3e Уз = 2c3e
Solve the following system 3 Y1 = -y1 1 3/2 2 = Y2 + 5Y3 Y = 2y3 2уз (a) y1 = cie¯ + 2c3e2* C2e“ + C3e2 2cze2 (d) y1 = Cie' (c) Y1 = c1e¬² – c3e2a Y2 = C2eª (b) ул Ce- C3e2* 2x Y2 = c2e" + c3e2* Cze2r 92 = Y3 = 2cze2" -2x = cje 2x Y3 Y3 -2x Cze (е) Ул + 2c3e" -2x C2e 2x Y2 + cze" Y2 = C2e + Cze* -2x -2x Y3 2c3e Уз = 2c3e
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question

Transcribed Image Text:Solve the following system
3
y1 = -yı
= -Y1 – 5Y3
233
3/2
1
Y2 +,43
2y3
=
(a) yı = cie- + 2c3e2 (b) yı = ce¯* – C3e2 (c) y1 = cie*
= cje¯* + 2c3e² (b) y1 = c1e-
Y2 = c2e" + cze2*
Cze?¤
(c) y1 = c1e¯
2x
Y2 = cze" + c3e2*
Cze?
C2eª
Cze2r
92 =
Y3 = 2c3e2
-2x
= cje
Y3 = 2c3e2"
-2x
Сзе (е) у1 — Сје
Y3 = 2c3e2"
(d) ул
+ 2cze"
-
-2x
Y2 = C2e
+ C3e“
-2x
Y2 = C2e
+ C3e
2x
Y3
2c3e
Y3 = 2c3e
-2x
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