Solve the following problems. Write your answer on your answer sheet. 1. You want to estimate the mean gasoline price within your town to the margin of error of 5 centavos. Local newspaper reports the standard deviation for gas price in the area is 25 centavos. What sample size is needed to estimate the mean gas prices at 95% confidence level? un in 13.8

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Answer the no. 1 be on point on the answer the second pic is the example guide

Solve the following problems. Write your answer on your answer sheet.
1. You want to estimate the mean gasoline price within your town to the margin of
error of 5 centavos. Local newspaper reports the standard deviation for gas price in
the area is 25 centavos. What sample size is needed to estimate the mean gas prices
at 95% confidence level?
in 13.8
Transcribed Image Text:Solve the following problems. Write your answer on your answer sheet. 1. You want to estimate the mean gasoline price within your town to the margin of error of 5 centavos. Local newspaper reports the standard deviation for gas price in the area is 25 centavos. What sample size is needed to estimate the mean gas prices at 95% confidence level? in 13.8
Solution:
Steps
1. Determine the given.
2. Determine the
confidence coefficient
3. Substitute the values
in the formula and
n=
compute.
2
n =
n=
E
1.29
n=
0.06
n = (21.5)²
n = 462.25 or 463
4. Round up the resulting
value to the nearest Thus, Mario needs a sample size of 463.
whole number.
Note: When Determining sample size, we always round up the resulting value to
the next whole number.
Rule: When the calculated sample size is not a whole number, it should
be rounded up to the next higher whole number.
Rule: Rounding up a sample size calculation for conservativeness ensures that
your sample size will always be the representative of the population.
https://www.isixsigma.com/tools-templates/sampling-data/rounding-and-round-rules
Reference:
Solution
99% confidence, E = 0.06 kg, o = 0.5 kg
a 100% - 99%
a = 1.99
a = .01
a/2 = 0.01/2
a/2 = 0.005
0.500 0.005 = 0.495
Za/2=1.96
To determine the value of
a, we can simply subtract
the confidence level from
100%.
Division property of
equality.
Subtract 0.005 from
0.500.
Hence, Using the Area
under the Standard
Normal Curve Table.
· 0
E
(2.58) (0.5)
0.06
2
2
Transcribed Image Text:Solution: Steps 1. Determine the given. 2. Determine the confidence coefficient 3. Substitute the values in the formula and n= compute. 2 n = n= E 1.29 n= 0.06 n = (21.5)² n = 462.25 or 463 4. Round up the resulting value to the nearest Thus, Mario needs a sample size of 463. whole number. Note: When Determining sample size, we always round up the resulting value to the next whole number. Rule: When the calculated sample size is not a whole number, it should be rounded up to the next higher whole number. Rule: Rounding up a sample size calculation for conservativeness ensures that your sample size will always be the representative of the population. https://www.isixsigma.com/tools-templates/sampling-data/rounding-and-round-rules Reference: Solution 99% confidence, E = 0.06 kg, o = 0.5 kg a 100% - 99% a = 1.99 a = .01 a/2 = 0.01/2 a/2 = 0.005 0.500 0.005 = 0.495 Za/2=1.96 To determine the value of a, we can simply subtract the confidence level from 100%. Division property of equality. Subtract 0.005 from 0.500. Hence, Using the Area under the Standard Normal Curve Table. · 0 E (2.58) (0.5) 0.06 2 2
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