Solve the following problems. Write your answer on your answer sheet. 1. You want to estimate the mean gasoline price within your town to the margin of error of 5 centavos. Local newspaper reports the standard deviation for gas price in the area is 25 centavos. What sample size is needed to estimate the mean gas prices at 95% confidence level? un in 13.8
Solve the following problems. Write your answer on your answer sheet. 1. You want to estimate the mean gasoline price within your town to the margin of error of 5 centavos. Local newspaper reports the standard deviation for gas price in the area is 25 centavos. What sample size is needed to estimate the mean gas prices at 95% confidence level? un in 13.8
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Answer the no. 1 be on point on the answer the second pic is the example guide
![Solve the following problems. Write your answer on your answer sheet.
1. You want to estimate the mean gasoline price within your town to the margin of
error of 5 centavos. Local newspaper reports the standard deviation for gas price in
the area is 25 centavos. What sample size is needed to estimate the mean gas prices
at 95% confidence level?
in 13.8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff07eb015-9472-4ee3-8045-20f3709f2df5%2Fed6f7be9-83aa-4ec3-a955-bebdb57f287c%2F1zrk60d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve the following problems. Write your answer on your answer sheet.
1. You want to estimate the mean gasoline price within your town to the margin of
error of 5 centavos. Local newspaper reports the standard deviation for gas price in
the area is 25 centavos. What sample size is needed to estimate the mean gas prices
at 95% confidence level?
in 13.8
![Solution:
Steps
1. Determine the given.
2. Determine the
confidence coefficient
3. Substitute the values
in the formula and
n=
compute.
2
n =
n=
E
1.29
n=
0.06
n = (21.5)²
n = 462.25 or 463
4. Round up the resulting
value to the nearest Thus, Mario needs a sample size of 463.
whole number.
Note: When Determining sample size, we always round up the resulting value to
the next whole number.
Rule: When the calculated sample size is not a whole number, it should
be rounded up to the next higher whole number.
Rule: Rounding up a sample size calculation for conservativeness ensures that
your sample size will always be the representative of the population.
https://www.isixsigma.com/tools-templates/sampling-data/rounding-and-round-rules
Reference:
Solution
99% confidence, E = 0.06 kg, o = 0.5 kg
a 100% - 99%
a = 1.99
a = .01
a/2 = 0.01/2
a/2 = 0.005
0.500 0.005 = 0.495
Za/2=1.96
To determine the value of
a, we can simply subtract
the confidence level from
100%.
Division property of
equality.
Subtract 0.005 from
0.500.
Hence, Using the Area
under the Standard
Normal Curve Table.
· 0
E
(2.58) (0.5)
0.06
2
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff07eb015-9472-4ee3-8045-20f3709f2df5%2Fed6f7be9-83aa-4ec3-a955-bebdb57f287c%2Fkwmhb4m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solution:
Steps
1. Determine the given.
2. Determine the
confidence coefficient
3. Substitute the values
in the formula and
n=
compute.
2
n =
n=
E
1.29
n=
0.06
n = (21.5)²
n = 462.25 or 463
4. Round up the resulting
value to the nearest Thus, Mario needs a sample size of 463.
whole number.
Note: When Determining sample size, we always round up the resulting value to
the next whole number.
Rule: When the calculated sample size is not a whole number, it should
be rounded up to the next higher whole number.
Rule: Rounding up a sample size calculation for conservativeness ensures that
your sample size will always be the representative of the population.
https://www.isixsigma.com/tools-templates/sampling-data/rounding-and-round-rules
Reference:
Solution
99% confidence, E = 0.06 kg, o = 0.5 kg
a 100% - 99%
a = 1.99
a = .01
a/2 = 0.01/2
a/2 = 0.005
0.500 0.005 = 0.495
Za/2=1.96
To determine the value of
a, we can simply subtract
the confidence level from
100%.
Division property of
equality.
Subtract 0.005 from
0.500.
Hence, Using the Area
under the Standard
Normal Curve Table.
· 0
E
(2.58) (0.5)
0.06
2
2
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