Solve the following problem using balanced binary search trees (TreeSet or TreeMap whichever is appropriate). Given array A of integers, and integer x, find a pair of integers ifj with A[i] + A] = x. The array is not sorted, but it does not contain duplicate elements. If there are multiple pairs that sum to x, choose a pair in which the smaller of two elements is as big as possible. For example, if A = {3, 6, 4, 1, 5, 2} then sumOf(A, 8) returns {0, 4} corresponding to the pair A[0] = 3, A[4] = 5, whose sum is 8. Note that this pair is preferred to {1, 5}, because min(A[O], A[4]) = 3, which is bigger than min(A[1], A[5]) = 2.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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Solve the following problem using balanced binary search trees (TreeSet or TreeMap whichever is appropriate). Given array A of integers, and
integer x, find a pair of integers i #j with A[i]+ A[j] = x. The array is not sorted, but it does not contain duplicate elements. If there are multiple pairs
that sum to x, choose a pair in which the smaller of two elements is as big as possible. For example, if A = {3, 6, 4, 1, 5, 2} then sumOf(A, 8) returns
{0, 4} corresponding to the pair A[0] = 3, A[4] = 5, whose sum is 8. Note that this pair is preferred to (1, 5}, because min(A[0], A[4]) = 3, which is
bigger than min(A[1], A[5]) = 2.
%3D
%3D
%3D
%3D
Class Pair {
int one,
two;
Pair (int a, int b) {one
a; two
b;}
Pair sumOf (int [] A, int x)
//code to solve the problem; RT should be 0(n log n)
Transcribed Image Text:Solve the following problem using balanced binary search trees (TreeSet or TreeMap whichever is appropriate). Given array A of integers, and integer x, find a pair of integers i #j with A[i]+ A[j] = x. The array is not sorted, but it does not contain duplicate elements. If there are multiple pairs that sum to x, choose a pair in which the smaller of two elements is as big as possible. For example, if A = {3, 6, 4, 1, 5, 2} then sumOf(A, 8) returns {0, 4} corresponding to the pair A[0] = 3, A[4] = 5, whose sum is 8. Note that this pair is preferred to (1, 5}, because min(A[0], A[4]) = 3, which is bigger than min(A[1], A[5]) = 2. %3D %3D %3D %3D Class Pair { int one, two; Pair (int a, int b) {one a; two b;} Pair sumOf (int [] A, int x) //code to solve the problem; RT should be 0(n log n)
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