Solve the following LP problem using the simplex method min z = -5x₁ - 7x2 - 12x3 + x4 I s. t. 2x1+3x2+2x3 + x4≤ 38 3x1 + 2x2 + 4x3 − x4 ≤ 55 T1, T2, T3, T4 ≥ 0 Tini = (0,0,0,0)¹.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Please show all work when answering the simplex method question. The initial starting point is shown in the image. 

This is an ungraded lecture problem. 

### Problem Statement

Solve the following Linear Programming (LP) problem using the simplex method:

**Objective Function:**
\[
\min_{x} \ z = -5x_1 - 7x_2 - 12x_3 + x_4
\]

**Subject to the Constraints:**
1. \( 2x_1 + 3x_2 + 2x_3 + x_4 \leq 38 \)
2. \( 3x_1 + 2x_2 + 4x_3 - x_4 \leq 55 \)

**Non-negativity Constraints:**
\[ x_1, x_2, x_3, x_4 \geq 0 \]

**Initial Solution:**
\[ x_{\text{ini}} = (0, 0, 0, 0)^T \]

### Explanation

This problem involves minimizing a linear objective function subject to a set of linear inequalities and non-negativity constraints. The initial solution vector is \((0, 0, 0, 0)\). The simplex method will be applied to find the optimal solution that minimizes the objective function while satisfying all the given constraints.
Transcribed Image Text:### Problem Statement Solve the following Linear Programming (LP) problem using the simplex method: **Objective Function:** \[ \min_{x} \ z = -5x_1 - 7x_2 - 12x_3 + x_4 \] **Subject to the Constraints:** 1. \( 2x_1 + 3x_2 + 2x_3 + x_4 \leq 38 \) 2. \( 3x_1 + 2x_2 + 4x_3 - x_4 \leq 55 \) **Non-negativity Constraints:** \[ x_1, x_2, x_3, x_4 \geq 0 \] **Initial Solution:** \[ x_{\text{ini}} = (0, 0, 0, 0)^T \] ### Explanation This problem involves minimizing a linear objective function subject to a set of linear inequalities and non-negativity constraints. The initial solution vector is \((0, 0, 0, 0)\). The simplex method will be applied to find the optimal solution that minimizes the objective function while satisfying all the given constraints.
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