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Solve the following LP (noting that x2 is urs) x2 being urs reflects that the business can must purchase units if >0 but is able to sell units x2 < 0 Max z = 30x1 - 4x2 s.t. 5x1 <= 30 + x2 x1 <= 5 x1 >= 0; x2 urs after introducing x2' and x2" as called for, we have a standard max so there is no Big-M or two Phase needed. 1. in the first tableau the entries in the x2" column are what number times the entries in the x2' column 1 2. in the next tableau, the entries in the x2" column are what number times the entries in the x2' column 1 3. The optimal solution for z is 120 4. the optimal value for x2" is 6 5. the optimal value for x2 is 0

Solve the following LP (noting that x2 is urs) x2 being urs reflects that the business can must purchase units if >0 but is able to sell units x2 < 0 Max z = 30x1 - 4x2 s.t. 5x1 <= 30 + x2 x1 <= 5 x1 >= 0; x2 urs after introducing x2' and x2" as called for, we have a standard max so there is no Big-M or two Phase needed. 1. in the first tableau the entries in the x2" column are what number times the entries in the x2' column 1 2. in the next tableau, the entries in the x2" column are what number times the entries in the x2' column 1 3. The optimal solution for z is 120 4. the optimal value for x2" is 6 5. the optimal value for x2 is 0

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the following LP (noting that x2 is urs) x2 being urs reflects that the business can must purchase units if >0 but is able to sell units x2 < 0 Max z = 30x1 - 4x2 s.t. 5x1 <= 30 + x2 x1 <= 5 x1 >= 0; x2 urs after introducing x2' and x2" as called for, we have a standard max so there is no Big-M or two Phase needed. 1. in the first tableau the entries in the x2" column are what number times the entries in the x2' column 1 2. in the next tableau, the entries in the x2" column are what number times the entries in the x2' column 1 3. The optimal solution for z is 120 4. the optimal value for x2" is 6 5. the optimal value for x2 is 0
Transcribed Image Text:Solve the following LP (noting that x2 is urs) x2 being urs reflects that the business can must purchase units if >0 but is able to sell units x2 < 0 Max z = 30x1 - 4x2 s.t. 5x1 <= 30 + x2 x1 <= 5 x1 >= 0; x2 urs after introducing x2' and x2" as called for, we have a standard max so there is no Big-M or two Phase needed. 1. in the first tableau the entries in the x2" column are what number times the entries in the x2' column 1 2. in the next tableau, the entries in the x2" column are what number times the entries in the x2' column 1 3. The optimal solution for z is 120 4. the optimal value for x2" is 6 5. the optimal value for x2 is 0
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