Solve the following linear programming using the graphical method (corner pointmethod).yı = number of tons of heavy crude oil produced.y2 = number of tons of light crude oil produced.Minimize total cost : z= 2500 yı + 3000 y2Constraints :yı2 30 tons of heavy crude oily22 20 tons of light crude oilyı + y2 2 60 tons totalYı , y2 20 non-negative requirements

Answered: Solve the following linear programming…

Practical Management Science

6th Edition

ISBN:9781337406659

Author:WINSTON, Wayne L.

Publisher:WINSTON, Wayne L.

Chapter2: Introduction To Spreadsheet Modeling

Section: Chapter Questions

Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...

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Choose the correct letter of answer Sister Company has given the following production model : Max 18x; s.t. 9x ≤ 45; x ≥ 0. Using the trial and error method, identify the optimal solution value of x. a. 7b. 9c. 12d. 5
Suppose 100,000 lamps are to be manufactured annually. It costs $1 to store a lamp for 1 year, $500 to set up the factory to produce a batch of lamps and $5 to produce each lamp. A. If all lamps are produced in one batch find the total cost? B. If all lamps are produced in two batches of equal size, find the total cost? C. If the number of units in each batch is q, then how many batches are there? D. Find the number of lamps in each batch to minmize the total cost? E. What is the minimum cost? [ i need all answer i will upvote]
33 White & Becker Tools (W&B) requires 2,000 elec- tric motors next month for its product line of weed trimmers. Each motor is composed of three com- ponents: a coil, a shaft, and housing. W&B has the capability to produce these components or purchase them from an outside vendor. The costs of produc- ing them and purchasing them are shown in the following table. COMPONENT Coil Shaft Housing DEPART- MENT PRODUCTION COST PER UNIT Fabrication 0.5 Molding 0.4 Inspection 0.2 $2.60 $1.80 $1.40 The components that are produced by W&B must pass through three departments: fabrication, molding, and inspection. The number of hours each component requires in each department and the total number of hours available next month in each department are shown in the following table: 0.2 0.7 0.3 PURCHASE COST PER UNIT COIL SHAFT HOUSING AVAILABILITY (HR.) (HR.) (HR.) (HR.) $3.12 $2.16 $1.68 0.6 0.3 0.4 3,000 3,000 1,800 In order to determine the number of components that will be produced and the number…
Boysen produces enamel and acrylic paint from two particular raw materials M1 and M2. The following data provides the data regarding the production restrictions.
A linear programming computer package is needed. The Silver Star Bicycle Company will be manufacturing both men's and women's models for its Easy-Pedal 10-speed bicycles during the next two months. Management wants to develop a production schedule indicating how many bicycles of each model should be produced in each month. Current demand forecasts call for 150 men's and 125 women's models to be shipped during the first month and 200 men's and 150 women's models to be shipped during the second month. Additional data are shown. Model Men's Women's Production Costs men's model in month 1 women's model in month 1 $120 men's model in month 2 $90 Labor Requirements (hours) Assembly Manufacturing 2.0 1.6 bicycles 1.5 Last month the company used a total of 1,000 hours of labor. The company's labor relations policy will not allow the combined total hours of labor (manufacturing plus assembly) to increase or decrease by more than 100 hours from month to month. In addition, the company charges…
Problem 13-03 Algo (Solving Integer Optimization Problems with Excel Solver) Number of: Pattern 12ft. 15ft. 30ft. Trim Loss 1 0 1 10 ft. 2 4 0 3 8 4 5 STAR Co. provides paper to smaller companies whose volumes are not large enough to warrant dealing directly with the paper mill. STAR receives 100-feet-wide paper rolls from the mill and cuts the rolls into smaller rolls of widths 12, 15, and 30 feet. The demands for these widths vary from week to week. The following cutting patterns have been established: 2 2 Min s.t. 4 3 0 1 3 Trim loss is the leftover paper from a pattern (e.g., for pattern 4, 2(12) + 1(15) + 2(30) = 99 feet used resulting in 100-99 = 1 foot of trim loss). Orders in hand for the coming week are 5,670 12-foot rolls, 1,680 15-foot rolls, and 3,350 30-foot rolls. Any of the three types the open market at the selling price. No inventory is held. Pattern (a) Formulate an integer programming model that will determine how many 100-foot rolls to cut into each of the five…
If the profit per unit on Tables (T) increases to $750 and simultaneously the profit per unit on Chairs (C) increases to $425, determine the new objective function value. Variable Cells Variable Name Value Cost T C Constraints 1 Number Name 2 Final Reduced Objective Allowable Allowable 3 Tables 18 0 Chairs 30 0 Coefficient Increase Decrease 720 395 Cleaning 1920 0 Fabric 4480 0.125 4480 Final Shadow Constraint Allowable Allowable 2080 90 Value Price R.H. Side Increase Decrease Testing 1600 0.188 1600 65 $26.250 O $27.690 O $1,440 Must recalculate. Change violated the 100% nule $24.810 1120 25 1E+30 80 40 160 160 320
Crane Corporation manufactures a single product. Monthly production costs incurred in the manufacturing process are shown below for the production of 3800 units. The utilities and maintenance are mixed costs. The fixed portions of theses costs are 430 and 270, respectively. Production In Units 3800 Production Costs Direct Materials 7904 Direct Labor 15124 Utilities 1798 Property Taxes 1180 Indirect Labor 4484 Supervisory salaries 2100 Maintenance 1182 Depreciation 2650 Calculate the expected costs when product is 5,300 units
The following is a L.P.P: Max 10.3X1 -3.6X2 + 12X3 (Hundreds of dollars $) 5.t: (production capacity; hours) (warehouse capacity; hundreds of sq. ft.) X1 + X2 + 2X3 0 The optimal solution to the model as follows: Basis Cij 10.3X1 -3.6X2 12X3 OS1 OS2 OS3 RHS -1 18 S1 X1 X3 1 -1 11 10.3 1 1 -1 1 1 12 C-Z How much is the Absolut value of the reduced cost (in $) in the optimal solution? i.e Absolut value of |-5| = always = 5
4

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