Solve the following initial value problems. Is the solution that you found unique on some interval? Justify. (a) dy = 2x²y², y(1) = −1.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Solve the following initial value problems. Is the solution that you
found unique on some interval? Justify.
(a)
(b)
(c)
dx
dx
=
=
-
2x²y², y(1) = −1.
vy, y(0) = 1.
y(0) = 1.
x-
Y
9
Transcribed Image Text:Solve the following initial value problems. Is the solution that you found unique on some interval? Justify. (a) (b) (c) dx dx = = - 2x²y², y(1) = −1. vy, y(0) = 1. y(0) = 1. x- Y 9
Expert Solution
Step 1: write the differential equation in variable separable form

a) 

Given differential equation is fraction numerator d y over denominator d x end fraction equals 2 x squared y squared space space space comma space y left parenthesis 1 right parenthesis equals negative 1

now solving the differential equation

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