Solve the following ILP problem, a knapsack problem, using the branch-and-bound algorithm, and stating an "upper bound" and a "lower bound" at each node of your branch-and-bound process. Marimize z = subject to: 10z1 + 20r2 +30r3 521 + 6x2 + 7a3 < 15 1, a2, a3 € {0, 1}

Solve the following ILP problem, a knapsack problem, using the branch-and-bound algorithm, and stating an "upper bound" and a "lower bound" at each node of your branch-and-bound process. Marimize z = subject to: 10z1 + 20r2 +30r3 521 + 6x2 + 7a3 < 15 1, a2, a3 € {0, 1}

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Question

Solve the following ILP problem, a knapsack problem, using the branch-and-bound algorithm, and stating
an "upper bound" and a "lower bound" at each node of your branch-and-bound process.
Marimize z = 10a1 + 2022 + 30r3
subject to:
5x1 + 6x2 + 7a3 < 15
*1, 2, 23 € {0, 1}

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