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Solve the following exercise, find the resistant moment of the optimal section and guarantee structural safety. Mu and Vu Check b) Flexion Check c) Shear check Data F'c = 250 kg/cm2 Fy = 4,200 kg/cm2 q = 4,000 kg/m L = 4 m Beam with 2 equal spans: Load distributed in the 2 spans reactions 3qL R = R, = 8. 5 qL RR = 4 L sharp V der B (3L - 8x) 8 VAB = v izq =-vder VB 5qL =- 8 VBC = 8 - (13L – 8x) ,izq Vc flexors

Solve the following exercise, find the resistant moment of the optimal section and guarantee structural safety. Mu and Vu Check b) Flexion Check c) Shear check Data F'c = 250 kg/cm2 Fy = 4,200 kg/cm2 q = 4,000 kg/m L = 4 m Beam with 2 equal spans: Load distributed in the 2 spans reactions 3qL R = R, = 8. 5 qL RR = 4 L sharp V der B (3L - 8x) 8 VAB = v izq =-vder VB 5qL =- 8 VBC = 8 - (13L – 8x) ,izq Vc flexors

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Solve the following exercise, find the resistant moment of the optimal section and guarantee structural safety. a) Mu and Vu Check b) Flexion Check c) Shear check Data F'c = 250 kg/cm2 Fy = 4,200 kg/cm2 q = 4,000 kg/m L = 4 m Beam with 2 equal spans: Load distributed in the 2 spans reactions 3qL R = Rc 8 5 qL RB %3D L sharp y der (3L -8x) 8 VAB = bzi VB der =-VB 5 qL 8 VBC = - (13L – 8x) ,izq Vc 8 flexors MB 3L qx (3L – 4x) 8 МАВ %3D (21. – x)-(4x – 5L) BC M L" L 4 4 Mmáx M, 9qL² máx 3L %3= 8. 13L y x= M. for máx = 128
Transcribed Image Text:Solve the following exercise, find the resistant moment of the optimal section and guarantee structural safety. a) Mu and Vu Check b) Flexion Check c) Shear check Data F'c = 250 kg/cm2 Fy = 4,200 kg/cm2 q = 4,000 kg/m L = 4 m Beam with 2 equal spans: Load distributed in the 2 spans reactions 3qL R = Rc 8 5 qL RB %3D L sharp y der (3L -8x) 8 VAB = bzi VB der =-VB 5 qL 8 VBC = - (13L – 8x) ,izq Vc 8 flexors MB 3L qx (3L – 4x) 8 МАВ %3D (21. – x)-(4x – 5L) BC M L" L 4 4 Mmáx M, 9qL² máx 3L %3= 8. 13L y x= M. for máx = 128
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