Solve the following equation system by using 'gauss siedel iteration' method. Take initial values as C1=C2=C3%3D0. C, = (500 +2c2+ 3c3)/17 =( 200 +5c, +ac3)/al 17c - 2c, - 3c, = 500 -5c, +21c, – 2c, = 200 -5c, – 5c, +22c, = 30 11- %3D | 22/(236+2s+o) = { What is the value of C3 as a result of first iteration? A) 19.411764706 B) 21.804176216 C) 16.526610644 D) 11.804176216 E) 29.411764706

Find the charge q(t) on the capacitor and the current i(t) in the given LRC-series circuit. L = 5 1 h, R10, C = f, E(t) = 800 V, 9(0) = 0 C, i(0) = 0 A 4 40 q(t) = i(t) = A C Find the maximum charge on the capacitor. (Round your answer to three decimal places.) с

Q1: For the Karnaugh map in Figure shown below, add a 1 in the lower right cell (1010) and determine the resulting SOP expression. |x AB 8 00 OF 11 10 8 (0) 1 1 01 11 10 T C 1 1

Simplify following Boolean Expressions using Quine-McClukey tabular method. F(A,B,C,D,E,F)=Em(6,9,13,18,19,25,27,29,41,45,57,61)

Simplify the following Boolean function using sum-of-products format F(A,B,C,D) =E (0, 2, 3, 7, 8. 10. 11, 12, 13, 14, 15)

solve it with steps and details please

Using Python and the Runge-Kutta 45 method numerically solve the following force-damped harmonic oscillator equation x¨=-2ζω0x˙-ω02x+10sinωt with initial conditions x(0)=1 and x˙(0)=0. In addition, use ζ=110,ω0=10π and ω=ω0 for plot 1 and ω=2ω0 for plot 2 . Note, you will be solving the equation twice, one for a driving force equal to sinw0t and the second with a driving force equal to sin2w0t. h=0.1 and 0≤t≤40 Compare the number of steps used for RK45 with the a Forward Euler Solution using the same level of convergence as the RK45. Plot both solutions and the same graph.

"Use a Karnaugh map to write a Boolean equation for this function in minimized sum-of-products form."

Determine the existence of Euler and/or Hamilton circuits/paths. If your answer is "yes", please write the circuit and/or path. F F в A D E Figure (a) Figure (b) Euler circuit Yes/ No Euler path Yes/ No Hamilton circuit Yes/ No Hamilton path Yes/ No Figure (a) Figure (b) Yes/ No Yes/ No Yes/ No Yes/ No

Try to use Boolean Algebra to simplify following expressions to your best effort (1) F = AB+ ABCD+ ABDE+ ABCE+CDE (2) F = ACD+CD)+ BCD + ACD + ACD (3) F = A+ B+C+D (4) F = ABC + AB + AD+C+ BD (5) (A+B+CCD+(B+ +(8+T\ABD+ BC).