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Solve the following differential equations (DEs) or initial values problems (IVPS): (b) 2xy x²+1 – 2x – (2 – In(x² + 1))y' = 0, y(5) = 0 -

Solve the following differential equations (DEs) or initial values problems (IVPS): (b) 2xy x²+1 – 2x – (2 – In(x² + 1))y' = 0, y(5) = 0 -

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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how do you calculate the value for c ?

56) -(2 -In(x²+1) g' z o y(5)= 1 M=2x% -22 N z-2+ ln (x²t). Nx = 20 DE iJ exct My = 2X fom s) z -2x) dx zyln(x²r1) - x² + +(3) af = 41y)=-2 = 4(4) =-2y4c. In (x²+1) t tly) = -2 + n (u41) I mplicit Soluton s Dc=-25 i gln (x²eı1)- x² = c.
Transcribed Image Text:56) -(2 -In(x²+1) g' z o y(5)= 1 M=2x% -22 N z-2+ ln (x²t). Nx = 20 DE iJ exct My = 2X fom s) z -2x) dx zyln(x²r1) - x² + +(3) af = 41y)=-2 = 4(4) =-2y4c. In (x²+1) t tly) = -2 + n (u41) I mplicit Soluton s Dc=-25 i gln (x²eı1)- x² = c.
Solve the following differential equations (DEs) or initial values problems (IVPS): (b) - 2x – (2 – In(x² + 1))y' = 0, y(5) = 0 x2+1
Transcribed Image Text:Solve the following differential equations (DEs) or initial values problems (IVPS): (b) - 2x – (2 – In(x² + 1))y' = 0, y(5) = 0 x2+1
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