Solve the following differential equation by VARIATION OF PARAMETERS. y''+4y'+4y=x^2, y(0)=1/8 y'(0)=-2 . note: when solving using variation of parameters, the following formulas may be useful. integral [xe^x dx]=e^x * (-1+x) , integral [x^2 e^x dx]= e^x (2-2x+x^2) , Integral [x^3 e^x dx]=e^x (-3+6x-6x^2+4x^3)/8 show all steps please!!
Solve the following differential equation by VARIATION OF PARAMETERS. y''+4y'+4y=x^2, y(0)=1/8 y'(0)=-2 . note: when solving using variation of parameters, the following formulas may be useful. integral [xe^x dx]=e^x * (-1+x) , integral [x^2 e^x dx]= e^x (2-2x+x^2) , Integral [x^3 e^x dx]=e^x (-3+6x-6x^2+4x^3)/8 show all steps please!!
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the following differential equation by VARIATION OF PARAMETERS. y''+4y'+4y=x^2, y(0)=1/8 y'(0)=-2 . note: when solving using variation of parameters, the following formulas may be useful. integral [xe^x dx]=e^x * (-1+x) , integral [x^2 e^x dx]= e^x (2-2x+x^2) , Integral [x^3 e^x dx]=e^x (-3+6x-6x^2+4x^3)/8 show all steps please!!
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