Chapter5: Polynomial And Rational Functions
Section: Chapter Questions
Problem 27PT: Find the unknown value. 27. y varies jointly with x and the cube root of 2. If when x=2 and...
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Equations and Inequations
Equations and inequalities describe the relationship between two mathematical expressions.
Linear Functions
A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.
Question
![Solve the following D.Es:
dy
1. (x + 1) = x(y² + 1).
dx
2. x(2y – 3)dx + (x² + 1)dy = 0.
(x2+1)
3. хеУdy +
dx = 0.
y
4. x2(y? + 1)dx + yvx? + 1 dy = 0.
dx
5. sinx
+ cosh2y = 0.
dy
dx
(2ху
dy
= 0.
y
6.
7. Inx =
dy
y
8. Vx2 +1 dy + Jy2 - 1 dx = 0.
9. x²y = (1+ x)cscy.
dx
Find the general solution for of each of the following D.Es:
1. (x2 + y?)dx + xydy
2. (xex + y)dx - xdy = 0.
= 0.
3. (x sin - ycos2) dx + xcos dy = 0.
4. x?dy + (y2 - xy)dx = 0.
5. (х + у)dy — (х — у)dx %3D 0.
dy
6. = 2+ cos.
dx
7. (x + ycot-) dy - ydx = 0.
8. (xy + y?)dx = (x² + xy + y?)dy.
dy
9. x- y = Jx2 - y2.
dx](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F230ffa0e-b424-40b4-ade9-bc88d5a81f3b%2Fa2f77d01-fb81-4873-a53e-c35e2ee23950%2Fybqie2hk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve the following D.Es:
dy
1. (x + 1) = x(y² + 1).
dx
2. x(2y – 3)dx + (x² + 1)dy = 0.
(x2+1)
3. хеУdy +
dx = 0.
y
4. x2(y? + 1)dx + yvx? + 1 dy = 0.
dx
5. sinx
+ cosh2y = 0.
dy
dx
(2ху
dy
= 0.
y
6.
7. Inx =
dy
y
8. Vx2 +1 dy + Jy2 - 1 dx = 0.
9. x²y = (1+ x)cscy.
dx
Find the general solution for of each of the following D.Es:
1. (x2 + y?)dx + xydy
2. (xex + y)dx - xdy = 0.
= 0.
3. (x sin - ycos2) dx + xcos dy = 0.
4. x?dy + (y2 - xy)dx = 0.
5. (х + у)dy — (х — у)dx %3D 0.
dy
6. = 2+ cos.
dx
7. (x + ycot-) dy - ydx = 0.
8. (xy + y?)dx = (x² + xy + y?)dy.
dy
9. x- y = Jx2 - y2.
dx
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