Solve the following algebraically:  a) tan (theta)+cos(theta)/1+sin(theta)=sec (theta) b) 1-cos(2theta)/2= sin^2(theta)

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Q: Solve the following equation involving inverse trig Sin^-1 (theta)+tan^-1 (theta)=0

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Q: if a=cos^2x+sin^4x,then find x

A: Given,

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Q: csc tan ²¹ (-1)] = sec cos ¹ (-1/2) = -1

A: odd function even function

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A: a) We know that Therefore, we have

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A:

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A: Trigonometric

Q: (cos7x-cos5x)/(cos7+cos5x)=tan6xtanx

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