Solve the following 2nd order equation using the variation of parameter method: 1. y" - y = e" 2. (D² + 1)y = csc x 3. (D' - 1)y %3D х-1 4. (D² + 4)y = sin x

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A: Given that,

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A: Given: p = [7, 2] and q = [5, -1]

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Q: 8A · 19^.

A: The given expression is 64·83. The following rule is used in simplifying the given expression.…

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A: a)6x23x+3÷5xx2+3x+2b)x2+3x+2x2+4x+3÷x2-4x2+x-6c)3x2-6xx2-7x+10×x-512x2

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