Solve the equation. (x+ 3xy“) dx + e*y°dy = 0 Begin by separating the variables. Choose the correct answer below. y3 dy%3D 1+ 3y X Xp. et? OB. 1+ 3y* 4 dy x+3xy* dx D. The equation is already separated. An implicit solution in the form F(x,y) = C is = C, where C is an arbitrary constant. %3D (Type an expression using x and y as the variables.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Solve the equation.**

\[
(x + 3xy^4) \, dx + e^{x^2} y^3 \, dy = 0
\]

---

**Begin by separating the variables. Choose the correct answer below.**

- **A.**  \(\frac{y^3}{1 + 3y^4} \, dy = -\frac{x}{e^{x^2}} \, dx\)

- **B.**  \(\frac{y^3}{1 + 3y^4} \, dx = -\frac{x}{e^{x^2}} \, dy\)

- **C.**  \(\frac{dy}{dx} = -\frac{x + 3xy^4}{e^{x^2} y^3}\)

- **D.** The equation is already separated.

---

**An implicit solution in the form \( F(x, y) = C \) is** \(\boxed{}\) **= C, where C is an arbitrary constant.** 

*(Type an expression using x and y as the variables.)*
Transcribed Image Text:**Solve the equation.** \[ (x + 3xy^4) \, dx + e^{x^2} y^3 \, dy = 0 \] --- **Begin by separating the variables. Choose the correct answer below.** - **A.** \(\frac{y^3}{1 + 3y^4} \, dy = -\frac{x}{e^{x^2}} \, dx\) - **B.** \(\frac{y^3}{1 + 3y^4} \, dx = -\frac{x}{e^{x^2}} \, dy\) - **C.** \(\frac{dy}{dx} = -\frac{x + 3xy^4}{e^{x^2} y^3}\) - **D.** The equation is already separated. --- **An implicit solution in the form \( F(x, y) = C \) is** \(\boxed{}\) **= C, where C is an arbitrary constant.** *(Type an expression using x and y as the variables.)*
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