Solve the equation •y^'=y-xy^3 e^(-2x) ka Solve the equation -2x y' = y - xy³e-2 - e²x = y²(x² + c) e^2x=y^2 (x^2+c) • e³x = y² (x³ + c) O e^3x=y^2 (x^3+c)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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•Solve the equation
•y^'=y-xy^3 e^(-2x)
Solve the equation
y' = y - xy³e-2x
Ragna
e²x = y² (x² + c)
e^2x=y^2 (x^2+c)
e2x = y³(x² + c)
e^2x=y^3 (x^2+c)
●
e³x = y²(x³ + c)
e^3x=y^2 (x^3+c)
Transcribed Image Text:5 •Solve the equation •y^'=y-xy^3 e^(-2x) Solve the equation y' = y - xy³e-2x Ragna e²x = y² (x² + c) e^2x=y^2 (x^2+c) e2x = y³(x² + c) e^2x=y^3 (x^2+c) ● e³x = y²(x³ + c) e^3x=y^2 (x^3+c)
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