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Solve the equation y'-y=f(t), y(0)=0 t/2 3 where f(t)= a. 0≤t<6 t>6 C. (s)-1([1-6-6¹] y(t) = [cost+t-u(t-6)(t - 6 – cos(t – 6))]) b. y(t)=[sint +t-u(t - 6)(t – 6 — sin(t — 6))] y(t) = [sint +t-µ(t-6)(t-sin(t))]] d. y(t) = [sint +1-u(t-6)(t – 6 – sin(t – 6))] =

Solve the equation y'-y=f(t), y(0)=0 t/2 3 where f(t)= a. 0≤t<6 t>6 C. (s)-1([1-6-6¹] y(t) = [cost+t-u(t-6)(t - 6 – cos(t – 6))]) b. y(t)=[sint +t-u(t - 6)(t – 6 — sin(t — 6))] y(t) = [sint +t-µ(t-6)(t-sin(t))]] d. y(t) = [sint +1-u(t-6)(t – 6 – sin(t – 6))] =

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve the equation y'-y = f(t), y(0)=0 where f(t)= 0≤t<6 F(s) = [¹-3] t>6 52 a. y(t) == [cost+t-u(t-6)(t-6-cos(t - 6))]) y(t) = [sint+t-u(t-6)(t – 6 – sin(t – 6))] v(t)=[sint- -[sint+t-u(t-6)(t - sin(t))] d. y(t) ==[sint +1- µ(t – 6)(t – 6 — sin(t − 6))] b. C. t/2 3 1
Transcribed Image Text:Solve the equation y'-y = f(t), y(0)=0 where f(t)= 0≤t<6 F(s) = [¹-3] t>6 52 a. y(t) == [cost+t-u(t-6)(t-6-cos(t - 6))]) y(t) = [sint+t-u(t-6)(t – 6 – sin(t – 6))] v(t)=[sint- -[sint+t-u(t-6)(t - sin(t))] d. y(t) ==[sint +1- µ(t – 6)(t – 6 — sin(t − 6))] b. C. t/2 3 1
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