Solve the equation x" +2x'+2x=25(t-π), x(0)=0, x'(0)=0 a. x(t)==—=sin(2t) x(t)=[1-e-²¹-2te-²¹] + µ(t− 2)(t − 2)e−2(t− 2t) x(t)=2μ(t-π)e-t-)sin(t-1) b. c. d. x(t)=[2-e²µ(t− π) + eªu(t−2π)]e-²tsint e. x(t) == [1 +µ(t - π)]sin(2t)
Solve the equation x" +2x'+2x=25(t-π), x(0)=0, x'(0)=0 a. x(t)==—=sin(2t) x(t)=[1-e-²¹-2te-²¹] + µ(t− 2)(t − 2)e−2(t− 2t) x(t)=2μ(t-π)e-t-)sin(t-1) b. c. d. x(t)=[2-e²µ(t− π) + eªu(t−2π)]e-²tsint e. x(t) == [1 +µ(t - π)]sin(2t)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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21.as soon as possible please
![Solve the equation
x" + 2x' +2x = 25(t - π), x(0)=0, x'(0) = 0
= sin(2t)
a. x(t)=
b. x(t)=
=[1-6
c. x(t)=2μ(t)e-(-) sin(t-1)
d. x(t)=[2-e²u(t = π) +eªu(t−2π)]e-²¹ sint
e. x(t) =
O a
O b
O c
Od
O e
-e-21-2te-21] + µ(t-2)(t-2)e-2 (1-21)
= (1+µ
+μ(t - π)]sin(2t)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa72e8965-bd79-4464-a740-a72095a0be2c%2Fae30139b-ce3f-4a6b-8b16-ef7f05bfe867%2Fw2qv7mi_processed.png&w=3840&q=75)
Transcribed Image Text:Solve the equation
x" + 2x' +2x = 25(t - π), x(0)=0, x'(0) = 0
= sin(2t)
a. x(t)=
b. x(t)=
=[1-6
c. x(t)=2μ(t)e-(-) sin(t-1)
d. x(t)=[2-e²u(t = π) +eªu(t−2π)]e-²¹ sint
e. x(t) =
O a
O b
O c
Od
O e
-e-21-2te-21] + µ(t-2)(t-2)e-2 (1-21)
= (1+µ
+μ(t - π)]sin(2t)
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