Solve the equation for solutions in the interval [0°, 360°). 1 18) sin 20 %3D 2

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section: Chapter Questions
Problem 32RE
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O Solve the equation for solutions in the interval [0°, 360°).
18) sin 20
= -
Transcribed Image Text:O Solve the equation for solutions in the interval [0°, 360°). 18) sin 20 = -
Expert Solution
Step 1

Consider the given information.

sin2θ=-12

As, in the trigonometric ratio, the value is defined as,

sinπ3=sin12

So, apply the above condition.

2θ=210°+360°nθ=105°+180°n

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