Solve the equation below for X, assuming A, B, and C are n × n invertible matrices: A*B(2C + X) = l,

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Written Assignment Question 5? Please solve in details.
Let C = (AB)-1.
Since (AB)(AB)- = 1, then (AB)C = .
Multiply both sides of the equation on the left by A-1:
Regrouping the terms on the left side using the associative property:
A-(AB)C = A-.
(A-A)BC = A-1
IBC = A-1
BC = A-!
Then:
B-'BC = B-'A-1
IC = B-'A-
so C = B-'A-1.
Multiplying both sides of the equation on the left by B-1:
Thus, C = (AB)- = B-1A-1.
Example 8:
Solve the equation below for X, assuming A, B, and C are n x n invertible matrices:
C(B + X)A- = I
Solution:
Video Solution: http://youtu.be/r15VTZ_t_I?hd=1
We wish to isolate the matrix X.
First, to get rid of the Con the left side, we can multiply both sides of the equation on the left by C-1:
C(B + X)A-= I,
C-'C(B + X)A- =C-
(B + X)A- = C-1"
Now, to get rid of the A on the right side, we can multiply both sides of the equation on the right by A:
(B + X)A-'A = C-'A
B+ X = C-A
Finally, we can isolate X by subtracting B from both sides: X = C-A - B
Now try Written Assignment, Question 5:
Solve the equation below for X, assuming A, B, and C are n x n invertible matrices: A-1B(2C + X) = I,
Transcribed Image Text:Let C = (AB)-1. Since (AB)(AB)- = 1, then (AB)C = . Multiply both sides of the equation on the left by A-1: Regrouping the terms on the left side using the associative property: A-(AB)C = A-. (A-A)BC = A-1 IBC = A-1 BC = A-! Then: B-'BC = B-'A-1 IC = B-'A- so C = B-'A-1. Multiplying both sides of the equation on the left by B-1: Thus, C = (AB)- = B-1A-1. Example 8: Solve the equation below for X, assuming A, B, and C are n x n invertible matrices: C(B + X)A- = I Solution: Video Solution: http://youtu.be/r15VTZ_t_I?hd=1 We wish to isolate the matrix X. First, to get rid of the Con the left side, we can multiply both sides of the equation on the left by C-1: C(B + X)A-= I, C-'C(B + X)A- =C- (B + X)A- = C-1" Now, to get rid of the A on the right side, we can multiply both sides of the equation on the right by A: (B + X)A-'A = C-'A B+ X = C-A Finally, we can isolate X by subtracting B from both sides: X = C-A - B Now try Written Assignment, Question 5: Solve the equation below for X, assuming A, B, and C are n x n invertible matrices: A-1B(2C + X) = I,
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