Solve the differential equation [x a. b. C. d. y tan-¹ (²2)] dx + x tan¯¹ (2/1) dy = 0 c²(x²+y²) 2x tan¯¹ (½) = x ln 2y tan-¹ (²/2) -1 2ytan ¹ (²/2) = x ln = x ln -1 2x tan-¹ (²-) = x In | c²(x² + y²) | c² (x² + y²) y4 c²(x² + y²) y4
Solve the differential equation [x a. b. C. d. y tan-¹ (²2)] dx + x tan¯¹ (2/1) dy = 0 c²(x²+y²) 2x tan¯¹ (½) = x ln 2y tan-¹ (²/2) -1 2ytan ¹ (²/2) = x ln = x ln -1 2x tan-¹ (²-) = x In | c²(x² + y²) | c² (x² + y²) y4 c²(x² + y²) y4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve the differential equation with homogenous coefficient. Provide a test for homogeneity. Provide a complete solution. Use a handwritten and step-by-step calculation without the use of calculator. Explain the process and simplify your answer.
![Solve the differential equation
b.
C.
y tan−¹ (²)] dx + xtan¯¹ (2/2) dy = 0
| c² (x² + y²)
2x tan -¹ (²/2) = x ln
-1
2y tan ¹ (²)
(²/2) = x ln
2y tan¹ (²)
(²¾/²)
= x ln
2x tan-¹(²)
(²½⁄) = x ln
| c² (x² + y²)
| c² (x² + y²)
y4
|c² (x² + y²)
y4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda40bd18-c1dd-4e57-9230-545764e12e8e%2Ff6b7852f-e796-4acc-b227-75c9627d935d%2Fabkc4j8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Solve the differential equation
b.
C.
y tan−¹ (²)] dx + xtan¯¹ (2/2) dy = 0
| c² (x² + y²)
2x tan -¹ (²/2) = x ln
-1
2y tan ¹ (²)
(²/2) = x ln
2y tan¹ (²)
(²¾/²)
= x ln
2x tan-¹(²)
(²½⁄) = x ln
| c² (x² + y²)
| c² (x² + y²)
y4
|c² (x² + y²)
y4
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