Solve the DE. adB + Bda + аB(Зda + dB) 30 O Caß = e-3a -B -3a -B B = e3-a-B O CBa = e-(3a – B)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 6
Solve the DE.
adß + Bda + aB(3da + dB) = 0
CaB = e-3a-B
-3α-β
B = e3-a-B
Cβα-e-(3α - β)
Transcribed Image Text:Question 6 Solve the DE. adß + Bda + aB(3da + dB) = 0 CaB = e-3a-B -3α-β B = e3-a-B Cβα-e-(3α - β)
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