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SOLVE STEP BY STEP IN DIGITAL FORMAT 2. One of the ends of a line segment of length equal to 4 is the point P (2,-2); if the abscissa of the other extreme is (2), find its ordinate (two solutions). 3. One of the ends of a line segment of length equal to 10 is point B (-3, 6); if the abscissa of the other extreme is (3), find its ordinate (two solutions).

SOLVE STEP BY STEP IN DIGITAL FORMAT 2. One of the ends of a line segment of length equal to 4 is the point P (2,-2); if the abscissa of the other extreme is (2), find its ordinate (two solutions). 3. One of the ends of a line segment of length equal to 10 is point B (-3, 6); if the abscissa of the other extreme is (3), find its ordinate (two solutions).

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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SOLVE STEP BY STEP IN DIGITAL FORMAT 2. One of the ends of a line segment of length equal to 4 is the point P (2,-2); if the abscissa of the other extreme is (2), find its ordinate (two solutions). 3. One of the ends of a line segment of length equal to 10 is point B (-3, 6); if the abscissa of the other extreme is (3), find its ordinate (two solutions).
Transcribed Image Text:SOLVE STEP BY STEP IN DIGITAL FORMAT 2. One of the ends of a line segment of length equal to 4 is the point P (2,-2); if the abscissa of the other extreme is (2), find its ordinate (two solutions). 3. One of the ends of a line segment of length equal to 10 is point B (-3, 6); if the abscissa of the other extreme is (3), find its ordinate (two solutions).
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Distance formula 

Let x1,y1 and (x2,y2) then the distance between the two points is, 

D=x2-x12+y2-y12

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