Solve solve this on emergency basis: find running Time complexity T(n) and Space complexity S(n). Also   show in big-O notation.   Code Segment 5 Algorithm Max (int a[], int size)      int max = a[0];      for (int i = 1; i < size / 2; ++i)      {            if (max < a[i])                 max = a[i];      }      for (int j = 1; j <= size * size; ++j)      {            ++max;            cout << max;      }

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A: Hello student Hope you are learning well.

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A: summary: - hence we discussed all the points

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A: The correct answer along with the explanation is given below:

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A: SUMMARY: - Hence, we discussed all the points.

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A: See the answer in second step.

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