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Solve solve this on emergency basis: find running Time complexity T(n) and Space complexity S(n). Also   show in big-O notation.   Code Segment 5 Algorithm Max (int a[], int size)      int max = a[0];      for (int i = 1; i < size / 2; ++i)      {            if (max < a[i])                 max = a[i];      }      for (int j = 1; j <= size * size; ++j)      {            ++max;            cout << max;      }

Solve solve this on emergency basis: find running Time complexity T(n) and Space complexity S(n). Also   show in big-O notation.   Code Segment 5 Algorithm Max (int a[], int size)      int max = a[0];      for (int i = 1; i < size / 2; ++i)      {            if (max < a[i])                 max = a[i];      }      for (int j = 1; j <= size * size; ++j)      {            ++max;            cout << max;      }

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Data Structyre and Algorithms:

Solve solve this on emergency basis:

find running Time complexity T(n) and Space complexity S(n). Also   show in big-O notation.

 

Code Segment 5

Algorithm Max (int a[], int size)

     int max = a[0];

     for (int i = 1; i < size / 2; ++i)

     {

           if (max < a[i])

                max = a[i];

     }

     for (int j = 1; j <= size * size; ++j)

     {

           ++max;

           cout << max;

     }

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