Solve sin x = cos x where x is in the interval [0,1]. Copy and paste from here: it Method 1: Square both sides to get sin²x = cos²x Replace cos² x by 1 - sin² x to get 2sin²x = or sin x = +√2/2. The latter has the solutions x = π/4 and x = Method 2: divide both sides by cos x to get tan x = This gives x = in the interval [0.π]. , both in the interval [0,π].
Solve sin x = cos x where x is in the interval [0,1]. Copy and paste from here: it Method 1: Square both sides to get sin²x = cos²x Replace cos² x by 1 - sin² x to get 2sin²x = or sin x = +√2/2. The latter has the solutions x = π/4 and x = Method 2: divide both sides by cos x to get tan x = This gives x = in the interval [0.π]. , both in the interval [0,π].
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Solve sin x = cos x where x is in the interval [0,1]. Copy and paste from here: I
Method 1: Square both sides to get sin²x = cos²x
Replace cos² x by 1 - sin² x to get 2sin²x =
or sin x = +√2/2.
The latter has the solutions x = π/4 and x =
Method 2: divide both sides by cos x to get
tan x =
both in the interval [0,π].
This gives x =
in the interval [0,1].
The two methods give different answers since in Method
equivalent equation. Therefore, the solutions need to be checked.
◆, the first step leads to a non-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd1a1f503-504e-4e54-b1b4-a9349f6634ba%2F3135d9e5-38c3-4edb-b178-20ac345ccd87%2Fxod2jtp_processed.png&w=3840&q=75)
Transcribed Image Text:Solve sin x = cos x where x is in the interval [0,1]. Copy and paste from here: I
Method 1: Square both sides to get sin²x = cos²x
Replace cos² x by 1 - sin² x to get 2sin²x =
or sin x = +√2/2.
The latter has the solutions x = π/4 and x =
Method 2: divide both sides by cos x to get
tan x =
both in the interval [0,π].
This gives x =
in the interval [0,1].
The two methods give different answers since in Method
equivalent equation. Therefore, the solutions need to be checked.
◆, the first step leads to a non-
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