Solve sin (x) + cos (x) = 1 on the interval [0,27]. Let's start the solving process as following, Steps Comment Step 1: [ sin(x) + cos(x)]² = 1² Step 2: sin?(x) + 2sin (x)cos (x) + cos²(x) = 1 Step 3: 1+ 2sin (x)cos (x) = 1 Raise both sides to square. Using complete square formula. Using identity sin²(x)+ cos²(x) = 1. Minus 1 from both sides in step 3. Step 4: 2si n(x) co s(x) = 0 Step 5: Please choose one of the routes listed below to continue the process. Route A: si n(x) = 0 or cos(x) = 0 0Or Route B: si n(2x) = 0 In Step 5, I would choose Route A O Route B

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