Solve sin (x) + cos (x) = 1 on the interval [0,27]. Let's start the solving process as following, Steps Comment Step 1: [ sin(x) + cos(x)]² = 1² Step 2: sin?(x) + 2sin (x)cos (x) + cos²(x) = 1 Step 3: 1+ 2sin (x)cos (x) = 1 Raise both sides to square. Using complete square formula. Using identity sin²(x)+ cos²(x) = 1. Minus 1 from both sides in step 3. Step 4: 2si n(x) co s(x) = 0 Step 5: Please choose one of the routes listed below to continue the process. Route A: si n(x) = 0 or cos(x) = 0 0Or Route B: si n(2x) = 0 In Step 5, I would choose Route A O Route B
Solve sin (x) + cos (x) = 1 on the interval [0,27]. Let's start the solving process as following, Steps Comment Step 1: [ sin(x) + cos(x)]² = 1² Step 2: sin?(x) + 2sin (x)cos (x) + cos²(x) = 1 Step 3: 1+ 2sin (x)cos (x) = 1 Raise both sides to square. Using complete square formula. Using identity sin²(x)+ cos²(x) = 1. Minus 1 from both sides in step 3. Step 4: 2si n(x) co s(x) = 0 Step 5: Please choose one of the routes listed below to continue the process. Route A: si n(x) = 0 or cos(x) = 0 0Or Route B: si n(2x) = 0 In Step 5, I would choose Route A O Route B
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![Solve sin (x) + cos (x) = 1 on the interval [0,27].
Let's start the solving process as following,
Steps
Comment
Step 1: [ sin(x) + cos(x)]² = 1²
Step 2: sin?(x) + 2sin (x)cos (x) + cos²(x) = 1
Step 3: 1+ 2sin (x)cos (x) = 1
Raise both sides to square.
Using complete square formula.
Using identity sin²(x)+ cos²(x) = 1.
Minus 1 from both sides in step 3.
Step 4: 2si n(x) co s(x) = 0
Step 5: Please choose one of the routes listed below to continue the process.
Route A: si n(x) = 0 or cos(x) = 0 0Or
Route B: si n(2x) = 0
In Step 5, I would choose
Route A
O Route B](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9f5f7c0-d9a9-4b8c-a25b-410d4ba0037a%2F47bd5a4b-62f3-4642-bebc-7d4875374225%2F83kdhj_processed.png&w=3840&q=75)
Transcribed Image Text:Solve sin (x) + cos (x) = 1 on the interval [0,27].
Let's start the solving process as following,
Steps
Comment
Step 1: [ sin(x) + cos(x)]² = 1²
Step 2: sin?(x) + 2sin (x)cos (x) + cos²(x) = 1
Step 3: 1+ 2sin (x)cos (x) = 1
Raise both sides to square.
Using complete square formula.
Using identity sin²(x)+ cos²(x) = 1.
Minus 1 from both sides in step 3.
Step 4: 2si n(x) co s(x) = 0
Step 5: Please choose one of the routes listed below to continue the process.
Route A: si n(x) = 0 or cos(x) = 0 0Or
Route B: si n(2x) = 0
In Step 5, I would choose
Route A
O Route B
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