Solve for y: y = sin (arctan (x/2)) O cannot be determined Vx2 +4 Va2+4 2)

Q: 1 |dx I (sec² x csc* x.

A: Integration gives the function whose derivative is given. It is nothing but adding all to make…

Q: Differentiate y = sin (x 2)

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Q: QI) Show that: (a) (1+x)° =1+6x (b) (cosx) = –sinx dx

A: 1.  a  1+x6≅1+6xb  ddxcos x=-sin x

Q: sin(cos¬1/2x²) = v3x? sO:

A: Given:   SinCos-1 2x2=3x2   To find out: x=?

Q: D?/if w= Cos (X+y)+Sin (X-y) Show that

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Q: d/dx -2(sin2x+cosxsinx)

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Q: Find if, y - x = sin(xy)

A: In this question we will use differentiation property for solving this question and after that we…

Q: cos 2x 12) S 2cos2x sin x – sin x dx -

A: To integrate:∫cos2x2cos2xsinx-sinxdx Solution: ∫cos2x2cos2xsinx-sinxdx On simplifying further we…

Q: Solve csc y dx + sec²x dy = 0 elect one: a 4cosy + 2x - sin2x = c O b. 4cosy + 2x + sin2x = c c.…

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Q: csch (2 sin2x) dx 1. V1-4x² r(²-1)cos[cosh (In r)]dr OS 4.

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Q: C- Find f' of the following: 1) √2x³-2² + In ² 2) 3xe³r+1 3) sin ¹(³).

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Q: 7/4 (sec² x – sin x)dx

A: 1. ∫sec2x dx=tanx 2. ∫sinx dx=-cosx 3.∫(u±v)dx=∫u dx±∫v dx 4. ∫abf(x) dx=F(b)-F(a), where ∫f(x)…

Q: 4 fcos 3x sin³ 3x dx

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Q: Solve cosx dx + (sinx)y=1 Select one: O ay sinx + ccosx O b. y = 2sinx + 2cosx + c O c. y = sinx –…

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Q: Differentiate y= cos y2x +1 sin 2x+1 A. V2x+1 sin 2x+1 B. V2x+1 sin 2x+1 C. V2x-1 sin 2x-1 D. V2x+1

A: Please refer the attached image for complete solution. THANK YOU.

Q: (Sin ² x - y) dx - tanx dy =o

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Q: 3x dx 1. S 2x 4-1

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Q: A particular solution of y" + y =sinx + xcosx a. x?sinx - 2xcosx) 4 b. (x?sinx – xcosx) 4 c. (x?sinx…

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Q: Ssin8 (3z) cos5 (3z) dz

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Q: 2) y = sin(3x²ex)

A: Find the derivative

Q: 6) y = (sin¬1 8t) (sec -1 derive

A: First, we use the product rule

Q: Find dy dx if sin(x + y) = tan(xy)

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Q: Solve the Bernoulli's equation given below: dy 2 dx -y cot2x = y' csc2x O A. [(y )^(- 2)] sin 2x = -…

A: Use Bernoulli theorem to solve

Q: Find JO cos²x - sin²x sinx + cos dx Please show your method.

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Q: What is y = sin (xy)

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Q: y = Secx ( sinx+ Cosx)

A: Given, y=secxsinx+cosx And we have to find the dydx.