Solve for x. x = [x] 71° (10x + 6) (13х - 2)° (8х- 1)

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Q: 15. Solve for x. 71° (10x + 6)° (13x – 2)° (8x-1)

A: The 4 sided polygon has measures (10x+6), (13x-2), (8x-1) and outer measure 71 degree.

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A: Given,

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A: We can find the answer as below.

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Q: 22х+5 3. х2+20 dx

A: We have  (3) I=∫22x+5x2+20 dx We can write as I=22∫xx2+20+5∫ 1x2+20dxI=22I1+5I2

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Q: 8. Solve for x. (3r+ 27) (8r-12)

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Q: sin 0 = sin 2e %3D T 3n 5T 1ln A) 3 4 3 6 5T It, 3 B) 0. 3 7n 11T C) {0, T} D) 0, 6 6 6. 6.

A: We will simply  the equation first and then find values of theta that satisfy the equation

Q: [s sec³ x tan5 x dx

A: The given integral is sec3x tan5x.