Solve for x. Show all work.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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## Instruction
Solve for \( x \). Show all work.

## Diagram Explanation

In the diagram, we have a circle with two intersecting chords. The lengths of the segments of the chords are given as follows:
- One chord is divided into segments of lengths 15 and 9.
- The other chord is divided into segments of lengths 6 and \( x \).

## Solution Description

To solve for \( x \) in this context, we will use the intersecting chords theorem, which states that for two intersecting chords in a circle, the products of the lengths of the segments of each chord are equal. 

Mathematically, this is expressed as:
\[ (part_1 \times part_2) = (part_3 \times part_4) \]

Given the lengths from the diagram:
\[ 15 \times 9 = 6 \times x \]

First, calculate the product on the left side:
\[ 15 \times 9 = 135 \]

Set up the equation:
\[ 135 = 6 \times x \]

Now, solve for \( x \):
\[ x = \frac{135}{6} \]

Simplify the fraction:
\[ x = 22.5 \]

Therefore, the value of \( x \) is 22.5.
Transcribed Image Text:## Instruction Solve for \( x \). Show all work. ## Diagram Explanation In the diagram, we have a circle with two intersecting chords. The lengths of the segments of the chords are given as follows: - One chord is divided into segments of lengths 15 and 9. - The other chord is divided into segments of lengths 6 and \( x \). ## Solution Description To solve for \( x \) in this context, we will use the intersecting chords theorem, which states that for two intersecting chords in a circle, the products of the lengths of the segments of each chord are equal. Mathematically, this is expressed as: \[ (part_1 \times part_2) = (part_3 \times part_4) \] Given the lengths from the diagram: \[ 15 \times 9 = 6 \times x \] First, calculate the product on the left side: \[ 15 \times 9 = 135 \] Set up the equation: \[ 135 = 6 \times x \] Now, solve for \( x \): \[ x = \frac{135}{6} \] Simplify the fraction: \[ x = 22.5 \] Therefore, the value of \( x \) is 22.5.
### Geometry Problem

**Problem Statement:**
Given a circle with points \( A \), \( B \), and \( C \) on its circumference, where point \( A \) is also the point of tangency with the tangent line, and \( \angle CAB \) is given as \( 101^\circ \). You are required to find the measure of the arc \( AB \).

**Diagram Explanation:**
- The circle shown has points \( A \) and \( B \) on its circumference.
- Point \( C \) is another point on the circumference such that line segment \( CA \) is drawn.
- \( \angle CAB \) is an inscribed angle which measures \( 101^\circ \).
- There is a tangent line at point \( A \).

**Multiple Choice Options:**
1. \( 202^\circ \)
2. \( 180^\circ \)
3. \( 50.5^\circ \)
4. \( 101^\circ \)

**Solution:**
In a circle, the measure of the arc intercepted by an inscribed angle is twice the measure of the angle. Therefore, if \( \angle CAB \) measures \( 101^\circ \), the measure of the arc \( AB \) that it intercepts is:

\[ \text{m} \overset{\frown}{AB} = 2 \times 101^\circ = 202^\circ \]

Therefore, the correct answer is:

- **202°**

**Answer:**
1. *202°*
Transcribed Image Text:### Geometry Problem **Problem Statement:** Given a circle with points \( A \), \( B \), and \( C \) on its circumference, where point \( A \) is also the point of tangency with the tangent line, and \( \angle CAB \) is given as \( 101^\circ \). You are required to find the measure of the arc \( AB \). **Diagram Explanation:** - The circle shown has points \( A \) and \( B \) on its circumference. - Point \( C \) is another point on the circumference such that line segment \( CA \) is drawn. - \( \angle CAB \) is an inscribed angle which measures \( 101^\circ \). - There is a tangent line at point \( A \). **Multiple Choice Options:** 1. \( 202^\circ \) 2. \( 180^\circ \) 3. \( 50.5^\circ \) 4. \( 101^\circ \) **Solution:** In a circle, the measure of the arc intercepted by an inscribed angle is twice the measure of the angle. Therefore, if \( \angle CAB \) measures \( 101^\circ \), the measure of the arc \( AB \) that it intercepts is: \[ \text{m} \overset{\frown}{AB} = 2 \times 101^\circ = 202^\circ \] Therefore, the correct answer is: - **202°** **Answer:** 1. *202°*
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