Solve for x. Round to the nearest tenth, if necessary. 17° 4.5

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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### Solving for x in a Right Triangle

**Problem Statement:**
Solve for \( x \). Round to the nearest tenth, if necessary.

**Diagram Description:**
A right triangle \( \Delta GHI \) is given with the following attributes:
- \( GH \) = 4.5 units
- \( \angle HGI \) = \( 90^\circ \)
- Side \( x \) is opposite the angle \( \angle GIH = 17^\circ \)

The lengths of the sides and angles are labeled on the triangle as follows:

- \( \angle IHG = 17^\circ \)
- \( GH = 4.5 \) (the side adjacent to the 17° angle)
- \( x \) is the hypotenuse 

Here is how you can solve for \( x \):

**Steps to Solution:**
To solve for \( x \), we can use trigonometric ratios, particularly the cosine function which is defined as:
\[ \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \]

In this triangle:
- The angle \( \theta = 17^\circ \)
- The adjacent side \( GH = 4.5 \)
- The hypotenuse is \( x \)

Using the cosine function:
\[ \cos(17^\circ) = \frac{4.5}{x} \]

Rearranging to solve for \( x \):
\[ x = \frac{4.5}{\cos(17^\circ)} \]

**Calculation:**

1. Find the cosine of 17 degrees using a calculator.
\[ \cos(17^\circ) \approx 0.9563 \]

2. Plug this value back into the equation:
\[ x = \frac{4.5}{0.9563} \approx 4.7 \]

**Solution:**
\[ x \approx 4.7 \]

Thus, the length of the hypotenuse \( x \) is approximately 4.7 units when rounded to the nearest tenth.
Transcribed Image Text:### Solving for x in a Right Triangle **Problem Statement:** Solve for \( x \). Round to the nearest tenth, if necessary. **Diagram Description:** A right triangle \( \Delta GHI \) is given with the following attributes: - \( GH \) = 4.5 units - \( \angle HGI \) = \( 90^\circ \) - Side \( x \) is opposite the angle \( \angle GIH = 17^\circ \) The lengths of the sides and angles are labeled on the triangle as follows: - \( \angle IHG = 17^\circ \) - \( GH = 4.5 \) (the side adjacent to the 17° angle) - \( x \) is the hypotenuse Here is how you can solve for \( x \): **Steps to Solution:** To solve for \( x \), we can use trigonometric ratios, particularly the cosine function which is defined as: \[ \cos(\theta) = \frac{\text{Adjacent}}{\text{Hypotenuse}} \] In this triangle: - The angle \( \theta = 17^\circ \) - The adjacent side \( GH = 4.5 \) - The hypotenuse is \( x \) Using the cosine function: \[ \cos(17^\circ) = \frac{4.5}{x} \] Rearranging to solve for \( x \): \[ x = \frac{4.5}{\cos(17^\circ)} \] **Calculation:** 1. Find the cosine of 17 degrees using a calculator. \[ \cos(17^\circ) \approx 0.9563 \] 2. Plug this value back into the equation: \[ x = \frac{4.5}{0.9563} \approx 4.7 \] **Solution:** \[ x \approx 4.7 \] Thus, the length of the hypotenuse \( x \) is approximately 4.7 units when rounded to the nearest tenth.
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