Solve for x. logx 8 = 3

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Solving Logarithmic Equations

**Problem Statement:**

Solve for \( x \).

\[ \log_x 8 = 3 \]

In this problem, you are given the logarithmic equation \(\log_x 8 = 3\). Your task is to determine the value of \( x \).

**Explanation:**

The logarithmic equation \(\log_x 8 = 3\) can be rewritten in its exponential form to make it easier to solve. The equation \(\log_b a = c\) is equivalent to \(b^c = a\).

So, applying this rule to \(\log_x 8 = 3\):

\[
x^3 = 8
\]

To solve for \( x \), you need to take the cube root of both sides of the equation:

\[
x = \sqrt[3]{8}
\]

Since the cube root of 8 is 2, we get:

\[
x = 2
\]

**Answer:**

\[ x = 2 \]

You can verify your solution by substituting \( x \) back into the original logarithmic equation to see if both sides equal.

\[ \log_2 8 = 3 \]

Since \( 2^3 = 8 \), the solution is correct.
Transcribed Image Text:### Solving Logarithmic Equations **Problem Statement:** Solve for \( x \). \[ \log_x 8 = 3 \] In this problem, you are given the logarithmic equation \(\log_x 8 = 3\). Your task is to determine the value of \( x \). **Explanation:** The logarithmic equation \(\log_x 8 = 3\) can be rewritten in its exponential form to make it easier to solve. The equation \(\log_b a = c\) is equivalent to \(b^c = a\). So, applying this rule to \(\log_x 8 = 3\): \[ x^3 = 8 \] To solve for \( x \), you need to take the cube root of both sides of the equation: \[ x = \sqrt[3]{8} \] Since the cube root of 8 is 2, we get: \[ x = 2 \] **Answer:** \[ x = 2 \] You can verify your solution by substituting \( x \) back into the original logarithmic equation to see if both sides equal. \[ \log_2 8 = 3 \] Since \( 2^3 = 8 \), the solution is correct.
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