Solve for x. (5x +9)° A- (7x-5)°

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Question
**Exercise: Solve for x**

**Diagram Explanation:**
The diagram represents an angle bisector. The line segment \(\overline{AB}\) acts as an angle bisector, meaning it divides the angle into two equal parts.

- The angle ∠A on the left is split into two parts:
  - The top part of the angle is labeled \((5x + 9)^\circ\).
  - The bottom part of the angle is labeled \((7x - 5)^\circ\).

Given information:
- \(\overline{AB}\) is an angle bisector.

Since \(\overline{AB}\) is an angle bisector, the two angles are equal. Therefore, we can set up the following equation to solve for \(x\):

\[5x + 9 = 7x - 5\]

To solve this equation:
1. Subtract \(5x\) from both sides:
   \[9 = 2x - 5\]
2. Add 5 to both sides:
   \[14 = 2x\]
3. Divide by 2:
   \[x = 7\]

So, the value of \( x \) is \( 7 \).
Transcribed Image Text:**Exercise: Solve for x** **Diagram Explanation:** The diagram represents an angle bisector. The line segment \(\overline{AB}\) acts as an angle bisector, meaning it divides the angle into two equal parts. - The angle ∠A on the left is split into two parts: - The top part of the angle is labeled \((5x + 9)^\circ\). - The bottom part of the angle is labeled \((7x - 5)^\circ\). Given information: - \(\overline{AB}\) is an angle bisector. Since \(\overline{AB}\) is an angle bisector, the two angles are equal. Therefore, we can set up the following equation to solve for \(x\): \[5x + 9 = 7x - 5\] To solve this equation: 1. Subtract \(5x\) from both sides: \[9 = 2x - 5\] 2. Add 5 to both sides: \[14 = 2x\] 3. Divide by 2: \[x = 7\] So, the value of \( x \) is \( 7 \).
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