) Solve for x: log4 x = 4

Q: solve for x (use log where is necessary ) 4sqrt(x)=8

A:

Q: ind x if: Loga (x + 4) - logą8 = loga4x

A: Given query is to find the value of x using properties of log.

Q: Solve for x, if (log 225/log15) = log x

A:

Q: Solve for x: 2logx=log2+log(3x−4) If one answer is x=2, what is the other value of x?

A: Given query is to find the value of x.

Q: Solve for x: log(x+4)= log(2x-1)

A: To solve the equation for x: log(x+4)=log(2x-1) Taking antilog both side we get, x+4=2x-1 =>…

Q: Solve for x. log, (-5x+8)= 1

A:

Q: Solve. log, x = 3 - log,(x - 2)

A: We know that, from the property of logarithm logam+logan=logamn           ⋯⋯1logab=c⇒ac=b        ⋯⋯2

Q: n: log, 4 = x

A:

Q: Solve for x log4 (x+12)=3

A: We have to solve for x   We have log4x+12=3 logba=c  ⇒  bc=a

Q: log4 (3x + 4)5 = 15

A: solve logrithm

Q: Solve for x: log x + log(x + 5) = 6

A: Consider the given equation logx+logx+5=6

Q: Solve for x: 4 log3 x = 7

A:

Q: Log, x= 34 x=3/4 16

A: The given logarithm is: log16x=34 To find the value of x.

Q: Solve for x. log4 (– 2x+4)=2

A:

Q: Solve for x. log x - log(x + 5) = -1

A: