Solve for x in the triangle. Round your answer to the nearest tenth. A 40° 10 X =

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Question
**Solve for \( x \) in the triangle. Round your answer to the nearest tenth.**

The image presents a right-angled triangle with one side labeled \( 10 \), one angle labeled \( 40^\circ \), and the hypotenuse labeled \( x \).

- **Triangle Diagram:**
  - The angle at the base of the triangle is \( 40^\circ \).
  - The side opposite the \( 40^\circ \) angle is the hypotenuse, labeled \( x \).
  - The side adjacent to the \( 40^\circ \) angle is labeled \( 10 \).
  - The right angle is at the lower left corner of the triangle.

The problem asks you to solve for \( x \), the hypotenuse, and round your answer to the nearest tenth.

**Solution Box:**
\[ 
x = \boxed{}
\]

**Icons:**
- An "X" icon likely to cancel the answer.
- A "reset" icon to clear the entered value.
- A question mark icon for help.

To solve for \( x \):
1. Use the cosine function: \(\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}\)
2. Here, \(\theta = 40^\circ\), \(\text{adjacent} = 10\), and \(\text{hypotenuse} = x\).
3. \(\cos(40^\circ) = \frac{10}{x}\)
4. Rearrange to solve for \( x \):
\[ 
x = \frac{10}{\cos(40^\circ)}
\]
5. Calculate using a calculator:
\[
\cos(40^\circ) \approx 0.766
\]
\[
x \approx \frac{10}{0.766} \approx 13.1
\]

So, the value of \( x \) rounded to the nearest tenth is \( 13.1 \).
Transcribed Image Text:**Solve for \( x \) in the triangle. Round your answer to the nearest tenth.** The image presents a right-angled triangle with one side labeled \( 10 \), one angle labeled \( 40^\circ \), and the hypotenuse labeled \( x \). - **Triangle Diagram:** - The angle at the base of the triangle is \( 40^\circ \). - The side opposite the \( 40^\circ \) angle is the hypotenuse, labeled \( x \). - The side adjacent to the \( 40^\circ \) angle is labeled \( 10 \). - The right angle is at the lower left corner of the triangle. The problem asks you to solve for \( x \), the hypotenuse, and round your answer to the nearest tenth. **Solution Box:** \[ x = \boxed{} \] **Icons:** - An "X" icon likely to cancel the answer. - A "reset" icon to clear the entered value. - A question mark icon for help. To solve for \( x \): 1. Use the cosine function: \(\cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}}\) 2. Here, \(\theta = 40^\circ\), \(\text{adjacent} = 10\), and \(\text{hypotenuse} = x\). 3. \(\cos(40^\circ) = \frac{10}{x}\) 4. Rearrange to solve for \( x \): \[ x = \frac{10}{\cos(40^\circ)} \] 5. Calculate using a calculator: \[ \cos(40^\circ) \approx 0.766 \] \[ x \approx \frac{10}{0.766} \approx 13.1 \] So, the value of \( x \) rounded to the nearest tenth is \( 13.1 \).
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