In the mechanism shown in figure. The angular velocity of link 2 is 100 rad/sec. CCW.Use loop closure and time derivative method for this analysis.Solve for w3 at instant when 02 = 90°. Use matrix formulation to solve theequations. Also solve for the velocity of point D at the instant 0₂ = 90°.BA3AB = 1.75 inAC = 2.5 inBD = 5 in

Answered: Solve for w3 at instant when 0₂ = 90°.…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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In the mechanism shown in figure. The angular velocity of link 2 is 100 rad/sec. CCW.
Use loop closure and time derivative method for this analysis.
Solve for w3 at instant when 02 = 90°. Use matrix formulation to solve the
equations. Also solve for the velocity of point D at the instant 0₂ = 90°.
B
A
3
AB = 1.75 in
AC = 2.5 in
BD = 5 in

Expert Solution

Step 1: Analysing given data

GIven,

$r subscript 2 equals 1.75 space i n r subscript 1 equals 2.5 space i n theta subscript 2 equals 90 degree ϕ equals tan to the power of negative 1 end exponent open parentheses fraction numerator 1.75 over denominator 2.5 end fraction close parentheses equals 34.992 degree r subscript 3 equals square root of 1.75 squared plus 2.5 squared equals end root 3.0516 space i n omega subscript 2 equals 100 space r a d divided by s e c$

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