Solve for the values of x₁, x₂ and x3using: 0.30x₁ +0.52x₂ +1.50x3 = -0.01 0.50x₁ + 1.25x₂ +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Gaussian Elimination b. Gauss-Jordan Elimination c. Gauss-Seidel Iteration. Use &, = 0.1%

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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3. Solve for the values of x₁, x2 and x3 using:
0.30x₁ +0.52x2 + 1.50x3 = -0.01
0.50x₁+1.25x2 +0.25x3 = 0.67
x₁ +0.30x₂ +0.50x3 = -0.44
Using:
a. Gaussian Elimination
b. Gauss-Jordan Elimination
c. Gauss-Seidel Iteration. Use &, = 0.1%
Transcribed Image Text:3. Solve for the values of x₁, x2 and x3 using: 0.30x₁ +0.52x2 + 1.50x3 = -0.01 0.50x₁+1.25x2 +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Gaussian Elimination b. Gauss-Jordan Elimination c. Gauss-Seidel Iteration. Use &, = 0.1%
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