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Solve for the values of x₁, x₂ and x3 using: 0.30x₂ +0.52x₂ +1.50x3 = -0.01 0.50x₂ +1.25x₂ +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Gauss-Jordan Elimination b. Gauss-Seidel Iteration. Use , = 0.1%. End if either of the unknows reach the stopping criterion.

Solve for the values of x₁, x₂ and x3 using: 0.30x₂ +0.52x₂ +1.50x3 = -0.01 0.50x₂ +1.25x₂ +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Gauss-Jordan Elimination b. Gauss-Seidel Iteration. Use , = 0.1%. End if either of the unknows reach the stopping criterion.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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5. Solve for the values of x₁, x2 and x3 using: 0.30x₁ +0.52x₂ + 1.50x3 = -0.01 0.50x₁ + 1.25x₂ +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Gauss-Jordan Elimination b. Gauss-Seidel Iteration. Use & = 0.1%. End if either of the unknows reach the stopping criterion.
Transcribed Image Text:5. Solve for the values of x₁, x2 and x3 using: 0.30x₁ +0.52x₂ + 1.50x3 = -0.01 0.50x₁ + 1.25x₂ +0.25x3 = 0.67 x₁ +0.30x₂ +0.50x3 = -0.44 Using: a. Gauss-Jordan Elimination b. Gauss-Seidel Iteration. Use & = 0.1%. End if either of the unknows reach the stopping criterion.
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