Solve for the unknown quantity for the following solutions. 13. How many grams of potassium nitrate are needed to make a 0.50 L solution at a concentration of 1.75 M? 14. What is the concentration of a solution made from dissolving 10.0 grams of sodium chloride in 350.0 mL of water? 15. What is the volume of solution that is 0.25 M and made from dissolving 33.4 grams of aluminum acetate in water? 16. What is the new concentration of a solution made by diluting 150.0 ml of 1.5 M copper(II) sulfate solution to 1.0 L? mol amount arity. tion 1. Ca ulate the

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Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.23E
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Set up for Solving 13-16?
Solve for the unknown quantity for the following solutions.
13. How many grams of potassium nitrate are needed to make a 0.50 L solution at a concentration of
1.75 M?
14. What is the concentration of a solution made from dissolving 10.0 grams of sodium chloride in 350.0 mL
of water?
15. What is the volume of solution that is 0.25 M and made from dissolving 33.4 grams of aluminum acetate
in water?
16. What is the new concentration of a solution made by diluting 150.0 ml of 1.5 M copper(II) sulfate
solution to 1.0 L?
M =
1. Calculate the Molarity/concentration
given amount solute and volume solute
2. Molarity is given
mol-amount
volume
use as a conversion factor
3. Dilution calculations
M₁ V₁ = M₂V₂
sig figs
plug back in to see if Correct
L
IL
XM → * mal OR
IL
x mal
Conversions from there
mar
M CUCI 2 V
Transcribed Image Text:Solve for the unknown quantity for the following solutions. 13. How many grams of potassium nitrate are needed to make a 0.50 L solution at a concentration of 1.75 M? 14. What is the concentration of a solution made from dissolving 10.0 grams of sodium chloride in 350.0 mL of water? 15. What is the volume of solution that is 0.25 M and made from dissolving 33.4 grams of aluminum acetate in water? 16. What is the new concentration of a solution made by diluting 150.0 ml of 1.5 M copper(II) sulfate solution to 1.0 L? M = 1. Calculate the Molarity/concentration given amount solute and volume solute 2. Molarity is given mol-amount volume use as a conversion factor 3. Dilution calculations M₁ V₁ = M₂V₂ sig figs plug back in to see if Correct L IL XM → * mal OR IL x mal Conversions from there mar M CUCI 2 V
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