Solve for the Resultant (Magnitude and Location x) for the parallel force system below. A 3 ft 3 kips 4 ft 10 kips 5 ft -2 kips/ft m B 6 ft

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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### Solving for the Resultant Force in a Parallel Force System

In this problem, we will determine the resultant force, along with its magnitude and location, for a given parallel force system.

### Problem Description

The figure provided illustrates a simply supported beam with two point loads and a uniformly distributed load. The beam has supports at points \( A \) and \( B \).

The forces acting on the beam are as follows:

1. A concentrated load of 3 kips located 3 ft from the support at \( A \).
2. A concentrated load of 10 kips located 7 ft from the support at \( A \).
3. A uniformly distributed load of 2 kips/ft acting over a span of 6 ft starting 13 ft from the support at \( A \).

### Force Diagram Explanation

- **Support Points**:
  - \( A \): Pin support.
  - \( B \): Roller support, located 12 feet from the pin support at \( A \).

- **Loads**:
  - **3 kips Load**: Applied vertically downward, located 3 ft from point \( A \).
  - **10 kips Load**: Applied vertically downward, located 7 ft from point \( A \).
  - **Uniform Load**: Distributed load of 2 kips/ft over a span of 6 ft, starting 13 ft from point \( A \).

### Steps to Solve the Problem

1. **Calculate the Resultant (Magnitude) of the Forces**:
   - Sum the concentrated loads.
   - Determine the equivalent point load for the uniformly distributed load.

2. **Determine the Position (Location \( x \)) of the Resultant Force**:
   - Calculate the moment of each force about point \( A \).
   - Compute the resultant moment using the principle of moments.

### Solving for the Magnitude of the Resultant Force

- **Resultant Force from Concentrated Loads**:
  \( F_{\text{resultant}} = 3 \text{ kips} + 10 \text{ kips} = 13 \text{ kips} \)

- **Resultant Force from Uniformly Distributed Load**:
  \( F_{\text{uniform}} = 2 \text{ kips/ft} \times 6 \text{ ft} = 12 \text{ kips} \)

- **Total Resultant Force**:
  \(
Transcribed Image Text:### Solving for the Resultant Force in a Parallel Force System In this problem, we will determine the resultant force, along with its magnitude and location, for a given parallel force system. ### Problem Description The figure provided illustrates a simply supported beam with two point loads and a uniformly distributed load. The beam has supports at points \( A \) and \( B \). The forces acting on the beam are as follows: 1. A concentrated load of 3 kips located 3 ft from the support at \( A \). 2. A concentrated load of 10 kips located 7 ft from the support at \( A \). 3. A uniformly distributed load of 2 kips/ft acting over a span of 6 ft starting 13 ft from the support at \( A \). ### Force Diagram Explanation - **Support Points**: - \( A \): Pin support. - \( B \): Roller support, located 12 feet from the pin support at \( A \). - **Loads**: - **3 kips Load**: Applied vertically downward, located 3 ft from point \( A \). - **10 kips Load**: Applied vertically downward, located 7 ft from point \( A \). - **Uniform Load**: Distributed load of 2 kips/ft over a span of 6 ft, starting 13 ft from point \( A \). ### Steps to Solve the Problem 1. **Calculate the Resultant (Magnitude) of the Forces**: - Sum the concentrated loads. - Determine the equivalent point load for the uniformly distributed load. 2. **Determine the Position (Location \( x \)) of the Resultant Force**: - Calculate the moment of each force about point \( A \). - Compute the resultant moment using the principle of moments. ### Solving for the Magnitude of the Resultant Force - **Resultant Force from Concentrated Loads**: \( F_{\text{resultant}} = 3 \text{ kips} + 10 \text{ kips} = 13 \text{ kips} \) - **Resultant Force from Uniformly Distributed Load**: \( F_{\text{uniform}} = 2 \text{ kips/ft} \times 6 \text{ ft} = 12 \text{ kips} \) - **Total Resultant Force**: \(
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