Solve for the missing measures in the diagram (side lengths and angles). Round the angle measures to the nearest tenth. The side length should be an integer. G m/G= mZH = GH = 12 5 H

Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
Question
**Solve for the missing measures in the diagram (side lengths and angles). Round the angle measures to the nearest tenth. The side length should be an integer.**

![Right Triangle Diagram]

- **Angle \( \angle G \) Measure (m\( \angle G \))**:
- **Angle \( \angle H \) Measure (m\( \angle H \))**:
- **Side Length \( GH \)**:

**Diagram Details:**

The diagram depicts a right triangle with the following information:

- Hypotenuse \( GH = 12 \)
- One leg \( IH = 5 \)
- The right angle \( \angle I \)

To find the missing measures:

1. **Finding Side \( GH \):**
   Use the Pythagorean theorem \( a^2 + b^2 = c^2 \):
   \[
   GI = \sqrt{12^2 - 5^2} = \sqrt{144 - 25} = \sqrt{119} \approx 10.9
   \]

2. **Finding the angles \( \angle G \) and \( \angle H \):**
   - \( \angle G = \arcsin\left(\frac{5}{12}\right) \approx 24.6^{\circ} \)
   - \( \angle H = 90^{\circ} - \arcsin\left(\frac{5}{12}\right) \approx 65.4^{\circ} \)

**Final Measures:**

- \( m\angle G = 24.6^{\circ} \)
- \( m\angle H = 65.4^{\circ} \)
- \( GH \approx 10.9 \)
Transcribed Image Text:**Solve for the missing measures in the diagram (side lengths and angles). Round the angle measures to the nearest tenth. The side length should be an integer.** ![Right Triangle Diagram] - **Angle \( \angle G \) Measure (m\( \angle G \))**: - **Angle \( \angle H \) Measure (m\( \angle H \))**: - **Side Length \( GH \)**: **Diagram Details:** The diagram depicts a right triangle with the following information: - Hypotenuse \( GH = 12 \) - One leg \( IH = 5 \) - The right angle \( \angle I \) To find the missing measures: 1. **Finding Side \( GH \):** Use the Pythagorean theorem \( a^2 + b^2 = c^2 \): \[ GI = \sqrt{12^2 - 5^2} = \sqrt{144 - 25} = \sqrt{119} \approx 10.9 \] 2. **Finding the angles \( \angle G \) and \( \angle H \):** - \( \angle G = \arcsin\left(\frac{5}{12}\right) \approx 24.6^{\circ} \) - \( \angle H = 90^{\circ} - \arcsin\left(\frac{5}{12}\right) \approx 65.4^{\circ} \) **Final Measures:** - \( m\angle G = 24.6^{\circ} \) - \( m\angle H = 65.4^{\circ} \) - \( GH \approx 10.9 \)
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