Solve for r: Given equation: log(15x – 5) – log r=1 O r = -11.00 O r=-5.00 Or 1.00 O= 15.00 O z 9.00

Q: Solve for x in the equation log(4) = -2. 2 8 16 64

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Q: Solve the equation for x: log, (x-5)+log, (x+3) =1

A: Consider the equation: log9x-5+log9x+3=1. Apply the log property logab+logac=logabc…

Q: for x: logs x + logs(x + 2) = 1

A: x= -4 or x= 2

Q: Solve for x in the following equations. 2. log(3x + 7) = 1 - log x

A: Formula used: The quadratic formula to solve the quadratic equation ax2+bx+c=0 x=-b±b2-4ac2a

Q: Solve for c: log, (9z + 2) = log, (x + 4)

A: Given: log29x+2=log2x+4

Q: Solve for a positive value of x. log, (32) – 5

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Q: Solve for x. log x = - 4 0.0001 -0.0001 1.386 -4

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Q: solve for y: logy = 2a+logb

A: We have to solve for y for the given equation, log y = 2a + log b

Q: Solve for a positive value of x. log,(x) = 2

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Q: Rewrite as a single logarithm: 5 log x - 2 log y + 4 log(x – y)

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Q: Solve for x:  log x + 2 log 2 = log 20 - log 10  and show all workings.

A: Solve for x:  log x + 2 log 2 = log 20 - log 10

Q: Solve for x: given log(17x – 3) – log æ = 1 -

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Q: Solve for using the definition of logarithm: (logx+29)- 2=0

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