Solve for P(X=130 | Y=15)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Solve for P(X=130 | Y=15)
Transcribed Image Text:Example 3.3. Plastic covers for CDs. Measurements for the length and width of a rectangular
plastic covers for CDs are rounded to the nearest mm. Let X denote the length and Y denote the
width. The possible values of X are 129, 130, and 131 mm. The possible values of Y are 15 and 16
mm. There are 6 possible pairs (X, Y). The probability for each pair is shown in the table below.
X=129 X=130 X=131
Y=15
0.12
0.42
0.06
Y=16
0.08
0.28
0.04
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