Solve for LA, LB, and x in the triangle listed below. X 4.32 см B 2.62cm

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The task is to solve for ∠A, ∠B, and x in the given right triangle.

### Diagram Description

1. **Triangle Labeling**:
   - The triangle is labeled with vertices A and B.
   - There is a right angle at vertex B.

2. **Side Lengths**:
   - The length of the side opposite angle A and adjacent to angle B is 2.62 cm.
   - The length of the side opposite angle B and adjacent to angle A is 4.32 cm.
   - The hypotenuse, opposite the right angle, is labeled as x.

### Analytical Steps

1. **Applying the Pythagorean Theorem**:  
   Use the formula \( a^2 + b^2 = c^2 \) where \( c \) is the hypotenuse.
   \[
   (2.62)^2 + (4.32)^2 = x^2
   \]

2. **Solving for x**:  
   Calculate the square of each side and solve for the hypotenuse.

3. **Trigonometric Ratios**:
   - Use sine and cosine ratios to find ∠A and ∠B.
   - \(\sin A = \frac{\text{opposite}}{\text{hypotenuse}} \)
   - \(\cos A = \frac{\text{adjacent}}{\text{hypotenuse}} \)

4. **Calculating Angles**:
   - Use inverse trigonometric functions to find the angles.
   - \(\angle A = \arcsin(\frac{2.62}{x})\)
   - \(\angle B = \arccos(\frac{2.62}{x})\)

After performing these calculations, you will have determined the measures of ∠A, ∠B, and the length of the hypotenuse, x.
Transcribed Image Text:The task is to solve for ∠A, ∠B, and x in the given right triangle. ### Diagram Description 1. **Triangle Labeling**: - The triangle is labeled with vertices A and B. - There is a right angle at vertex B. 2. **Side Lengths**: - The length of the side opposite angle A and adjacent to angle B is 2.62 cm. - The length of the side opposite angle B and adjacent to angle A is 4.32 cm. - The hypotenuse, opposite the right angle, is labeled as x. ### Analytical Steps 1. **Applying the Pythagorean Theorem**: Use the formula \( a^2 + b^2 = c^2 \) where \( c \) is the hypotenuse. \[ (2.62)^2 + (4.32)^2 = x^2 \] 2. **Solving for x**: Calculate the square of each side and solve for the hypotenuse. 3. **Trigonometric Ratios**: - Use sine and cosine ratios to find ∠A and ∠B. - \(\sin A = \frac{\text{opposite}}{\text{hypotenuse}} \) - \(\cos A = \frac{\text{adjacent}}{\text{hypotenuse}} \) 4. **Calculating Angles**: - Use inverse trigonometric functions to find the angles. - \(\angle A = \arcsin(\frac{2.62}{x})\) - \(\angle B = \arccos(\frac{2.62}{x})\) After performing these calculations, you will have determined the measures of ∠A, ∠B, and the length of the hypotenuse, x.
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